Given triangle ABC with coordinates A(−6, 4), B(−6, 1), and C(−8, 0), and its image A′B′C′ with A′(−2, 0), B′(−5, 0), and C′(−6,
Zinaida [17]
Answer:
The line of reflection is at y = x+6.
Step-by-step explanation:
The perpendicular bisector of AA' is a line with slope 1 through the midpoint of AA', which is (-4, 2). In point-slope form, the equation is ...
y = 1(x +4) +2
y = x + 6 . . . . . . . line of reflection
The text of the question is not visible in the answering window. I'll reproduce it here:
BD bisects <ABC.
m <ABD= 2.5x + 8.6
m<CBD = 3.5x - 3.4
Find m<ABC
Answer:

Step-by-step explanation:
We have an angle ABC and a line BD bisecting it.
If an angle is bisected, then the two formed angles are congruent, that is

Substituting the algebraic expressions for both angles:

Subtracting 8.6 and 3.5x:

Operating:


The two angles are:


As expected, both angles have the same measure.
The measure of the total angle ABC is twice any of those:


Answer:
top left
Step-by-step explanation: