First, you have to substitute for x, which would make the problem f(x)=7.45(-4.3)+33.7
Now, you just have to use the PEMDAS method (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction)
f(x)= -32.035+33.7
f(x)=1.665
Answer:
A - monthly payment: $1,580.89
Step-by-step explanation:
175 + 129 + 283 = 587
2,250 - 587 = 1,663
1989.23 (More then she has left
1790.25 (More then she has left
1580.89 (less then she has left
A > monthly payment: $1,580.89
Answer:
Step-by-step explanation:
Given question is incomplete: Find the compete question in the attachment.
a). Skew lines neither the parallel lines nor they intersect each other.
Two pairs of skew lines are BF and EH, & CG and EF.
b). Since EFGH and ABCD are rectangular planes and BF and DH are perpendicular to them,so both will be the altitudes between the planes.
Therefore, BF and DH will pe parallel.
c). BD and DH are the diagonals of the planes parallel to each other.
Therefore, BD and DH will be parallel.
d). Since BD and plane EFG don't intersect each other, so the solution will be an empty set.
e). HG is perpendicular to DH. So,the planes BDH and FHG containing these lines will be perpendicular to each other.
Answer:
The mistake is evidently in the addition of the first 5 bowling scores
Step-by-step explanation:
Brenda had bowling scores 92, 110, 85, 78, and 96.
She needs one more bowl to get an average of 96.
Let the last bowl score = x
(92 + 110 + 85 + 78 + 96 + x)/6 = 96
(92 + 110 + 85 + 78 + 96 + x) = 96×6 = 576
461 + x = 576
x = 576 - 461 = 115
The mistake is evidently in the addition of the first 5 bowling scores, the score for the 5th bowl was excluded, maybe because it was coincidentally 96 too.
She added (92 + 110 + 85 + 78) instead of (92 + 110 + 85 + 78 + 96), so, the score needed for the last bowl to get an average of 96 is actually 115, not 211.
Hope this Helps!!!
