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blondinia [14]
3 years ago
8

Amy owes her mother $76. She pays her mother $14 on Sunday and $24 on Monday. Use an expression to describe the situation. How m

uch does Amy still owe her mother?
Mathematics
1 answer:
bulgar [2K]3 years ago
3 0

Answer:

Amy still owes her mother $38.

Step-by-step explanation:

76 - 14 - 24

76 - 14 = 62

62 - 24 = 38

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A researcher wishes to estimate the proportion of adults who have​ high-speed Internet access. What size sample should be obtain
slega [8]

Answer: 8359

Step-by-step explanation:

The formula for sample size needed for interval estimate of population proportion :-

n=p(1-p)(\frac{z_{\alpha/2}}{E})^2

Given : The significance level : \alpha=1-0.95=0.05

Critical value : z_{\alpha/2}}=z_{0.025}=\pm1.96

Previous estimate of proportion : p=0.32

Margin of error : E=0.01

Now, the required sample size will be :-

n=0.32(1-0.32)(\frac{1.96}{0.01})^2=8359.3216\approx8359

Hence, the required sample size = 8359

5 0
3 years ago
WILL MARK BRAINLIEST
Sergeeva-Olga [200]

Answer:

a.$167.03

Step-by-step explanation:

6 0
2 years ago
Which ordered pair is a solution of the equation
andrew11 [14]
(0,-7)
-7=11(0)+4
-7=0+4
-7 is not 4 -----not a solution

(-1,-7)
-7=11(-1)+4
-7=-11+4
-7=-7 ----solution

(1,-7)
-7=11(1)+4
-7=11+4
-7=15
-7 is not 15 ----not a solution

(2,26)
26=11(2)+4
26=22+4
26=26 ----soltion

(-1, -7) & (2, 26) are solutions to the equation
4 0
3 years ago
Assume that you have a sample of n 1 equals 6​, with the sample mean Upper X overbar 1 equals 50​, and a sample standard deviati
tigry1 [53]

Answer:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

df=6+5-2=9

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

n_1 =6 represent the sample size for group 1

n_2 =5 represent the sample size for group 2

\bar X_1 =50 represent the sample mean for the group 1

\bar X_2 =38 represent the sample mean for the group 2

s_1=7 represent the sample standard deviation for group 1

s_2=8 represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 > \mu_2

We are assuming that the population variances for each group are the same

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic for this case is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

The pooled variance is:

S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

We can find the pooled variance:

S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67

And the pooled deviation is:

S_p=7.46

The statistic is given by:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

The degrees of freedom are given by:

df=6+5-2=9

The p value is given by:

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0
3 years ago
Is this linear relationship proportional or non-proportional? Y = 5x + 1
Tanya [424]
Plug in numbers in for x. 
If you plug in 0 then you get 1. 1/0 is undefined
If you plug in 1 then you get 6. 6/1 is 6
If you plug in 2 then you get 11. 11/2 is 5.5
If you plug in 3 then you get 16. 16/3 is 5.3 repeating
If you plug in 4 then you get 21. 21/4 is 5.25
If you plug in 5 then you get 26. 26/5 is 5.2
It would only be proportional if you got the same answer after dividing each time.
7 0
3 years ago
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