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Doss [256]
3 years ago
6

How many molecules of each of the cofactors are produced when two acetyl-SCoA molecules pass through the citric acid cycle?

Chemistry
1 answer:
professor190 [17]3 years ago
3 0

Answer:

Explanation:

1000

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14
Bond [772]

Answer:

Explanation:

The melting point of a substance is the temperature at which its melt. The state of a substance is dependent on it's melting temperature. Generally, melting point above 25 °C is a solid.

This means phenol is a solid

Duodecane has melting point below 25 °C hence it is either a liquid or gas. However its boiling point of 216 °C means it would require higher temperature to boil it. Since 25 °C is less than 216 °C it means that it would remain in the liquid state.

Methane has melting point below 25 °C hence it is either a liquid or gas. However its boiling point of -164 °C means it boils easily even at very low temperatures. Since 25 °C is greater than -164 °C it means that it would exist in the gaseous state

8 0
3 years ago
Succinate dehydrogenase catalyzes the conversion of succinate to fumarate. The reaction is inhibited by malonic acid, which rese
allsm [11]

Answer:

Here malonic acid acts as a competitive inhibitor of succinate dehydrogenase

Explanation:

Malonic acid structurally resembles succinic acid as a result the enzyme succinate dehydrogenase cannot distinguish between malonic acid and succinic acid.

      That"s why malonic acid interact with succinate dehydrogenase thereby blocking the catalytic activity of the later.

      As this mechanism is a type of competitive inhibition that"s why increasing the concentration of substrate succinic acid can reduce the inhibitory effect of malonic acid.

3 0
3 years ago
If I have 2 liters of gas held at a pressure of 78 atm and a temperature of 900 k, what will be the volume of the gas if I decre
dangina [55]

Answer:

V2 = 2.88L

Explanation:

P1= 78atm, V1= 2L, T1= 900K, P2= 45atm, V2=? T2= 750K

Applying the general gas equation

P1V1/T1 = P2V2/T2

Substitute the above

(78*2)/900= (45*V2)/750

V2= (78*2×750)/(900*45)

V2= 2.88L

7 0
3 years ago
Question 15 How many grams of NaCl are required to make 500.0 mL of a 1.500 M solution? 58.40 g 175.3 g 14.60 g 43.83 g
ExtremeBDS [4]
Hi!

To make 500 mL of a 1,500 M solution of NaCl you'll require 43,83 g

To calculate that, you will need to use a conversion factor to go from the volume of the 1,500 M solution to the required grams. For this conversion factor, you'll use the definition for Molar concentration (M=mol/L) and the molar mass of NaCl. The conversion factor is shown below:

gNaCl=500mLsol* \frac{1L}{1000 mL}* \frac{1,500 mol NaCl}{1Lsol}* \frac{58,4428 g NaCl}{1 mol NaCl} \\ =43,83gNaCl

Have a nice day!
4 0
3 years ago
What the first song come to your mind?
romanna [79]

Answer: Hey Brother by Avicii

4 0
3 years ago
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