The answer is 2 because you have to divide these numbers.<span />
I think c may be your anwser but im not too sure :/ srry if u get it wrong!
In a solution, when the concentrations of a weak acid and its conjugate base are equal: 1. the -log of the concentration of H+ and the -log of the Ka are equal.
<h3>What are Strong acid strong bases ?</h3>
Any acid that entirely ionises in solutions is considered a strong acid. When positioned, it emits the most hydrogen ions or protons.
- It is a substance with the capacity to take a proton out of an extremely weak acid. In water, they can also entirely separate into its ions. Examples include sodium hydroxide and potassium hydroxide (KOH) (NaOH)
<h3>What are weak acid and weak bases ?</h3>
Acids that don't entirely dissociate in solution are referred to as weak acids. In other words, any acid that is not a strong acid qualifies as a weak acid. The amount of dissociation determines how strong an acid is; the more dissociation, the stronger the acid.
- Weak bases are basic compounds that, when dissolved in solutions, do not entirely separate into their constituent ions.
Learn more about Acids and bases here:
brainly.com/question/27915098
#SPJ4
Physical change because water is not a gas or change . you can see through it.
Answer:
2.30 liters.
Explanation:
- The balanced equation of the reaction is:
<em>Na₂O₂ + CO₂ → Na₂CO₃ + 1/2O₂,</em>
- It is clear that 1.0 mole of Na₂O₂ reacts with 1.0 mole of CO₂ to produce 1.0 mole of Na₂CO₃ and 0.5 mole of O₂.
- The no. of moles of CO₂ in (4.60 L) reacted can be calculated from the relation: <em>PV = nRT</em>.
P is the pressure of the gas (P = 1.0 atm at STP),
V is the volume of the gas (V = 4.60 L),
R is the general gas constant (R = 0.082 L.atm/mol.K),
T is the temperature of the gas (T = 273.0 K at STP).
∴ n = PV/RT = (1.0 atm)(4.6 L) / (0.082 L.atm/mol.K)(273.0 K) = 0.205 mol.
<u><em>Using cross multiplication:</em></u>
1.0 mole of CO₂ produces → 0.5 mole of O₂, from the stichiometry.
0.205 mole of CO₂ produces → ??? mole of O₂.
- The no. of moles of O₂ produced from 4.60 L of CO₂ = (0.5 mole)(0.205 mole) / (1.0 mole) = 0.103 mole.
- ∴ The volume of O₂ produced from 4.60 L of CO₂ = nRT/P = (0.103 mol)(0.082 L.atm/mol.K)(273.0 K) / (1.0 atm) = 2.30 liters.