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gogolik [260]
3 years ago
5

How much mass of ice at 0℃ must melt when ∆Q=948000 J of heat energy is added to it?

Physics
1 answer:
butalik [34]3 years ago
6 0
<h2>The ice melted is nearly 2.8 kg </h2>

Explanation:

The quantity of heat required to melt the ice can be found by the relation .

ΔQ = m x L

here L is used for the latent heat of fusion .

Its value is 334 J per gram for ice .

Thus m = \frac{\Delta Q}{L} = \frac{948000}{334}  = 2836 gram

or = 2.8 kg approx

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The electric field in a particular thundercloud is 3.8 x 105 N/C. What is the acceleration (in m/s2) of an electron in this fiel
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Answer:

Answer:

6.68 x 10^16 m/s^2

Explanation:

Electric field, E = 3.8 x 10^5 N/C

charge of electron, q = 1.6 x 10^-19 C

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Let a be the acceleration of the electron.

The force due to electric field on electron is

F = q E

where q be the charge of electron and E be the electric field

F = 1.6 x 10^-19 x 3.8 x 10^5

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6.08 x 10^-14 = 9.1 x 10^-31 x a

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A 1350 kg car travels at 12 m/s. What is it's kinetic energy
Lana71 [14]

Hello!

A 1350 kg car travels at 12 m/s. What is it's kinetic energy ?

We have the following data:  

m (mass) = 1350 kg  

v (velocity) = 12 m/s  

KE (kinetic Energy) = ? (in Joule)  

Formula to calculate kinetic energy:

\boxed{KE = \dfrac{1}{2} *m*v^2}

Solving:

KE = \dfrac{1}{2} *m*v^2

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KE = \dfrac{1}{2} *1350*144

KE = \dfrac{194400}{2}

\boxed{\boxed{KE = 97200\:Joule}}\:or\:\boxed{\boxed{KE = 97.2\:kJ}}\Longleftarrow(kinetic\:energy)\:\:\:\:\:\:\bf\blue{\checkmark}

_______________________

\bf\green{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

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