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makvit [3.9K]
3 years ago
14

1. Vertically oriented circular disks have strings wrapped around them. The other ends of the strings are attached to

Physics
1 answer:
Ymorist [56]3 years ago
5 0

Answer:

See the answers and explanation below

Explanation:

To solve this problem, we must have the full description of this problem, by doing an internet search we can find a problem with the same description and with the respective question.

<u>Description of the problem</u>

<u />

"Vertically oriented circular disks have strings wrapped around them. The other ends of the strings are attached to  hanging masses. The diameters of the disks, the masses of the disks, and the masses of the hanging masses are

given. The disks are fixed and are not free to rotate. Specific values of the variables are given in the figures. Rank these situations, from greatest to least, on the basis of the magnitude of the torque on the disks. That is, put first the situation where the disk has the greatest torque acting on it and put last the situation where the disk has the least torque acting on it."

<u>For case D</u>

<u />

T = (20/2)*800 = 8000 [g-cm]

<u>For case A</u>

<u />

T = (20/2)*500 = 5000 [g-cm]

<u>For case C</u>

<u />

T = (10/2)*500 = 2500 [g-cm]

<u>For case B</u>

<u />

T = (10/2)*200 = 1000 [g-cm]

In this way it has been organized from the largest to the smallest torque present in each of the cases.

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Two astronauts push on a satellite. One pushes in the positive x direction with a force of 42 N, and the other pushes in the pos
inessss [21]

The vectors adition we can find the magnitude of the force applied by the other astronaut is  11.25 N in the y direction

 

Parameters given

  • Force of an astronaut Fₓ = 42 N
  • Angle θ = 15º

To find

  • Force another astronaut

The force is a vector magnitude for which the addition of vectors must be used, a very efficient method to perform this sum is to add the components of each vector and devise constructing the resulting vector using trigonometry and the Pythagorean theorem.

Let's use trigonometry to find the other force

            tan θ = \frac{F_y}{F_x}

            F_ y = Fₓ tan θ

let's calculate

            F_y = 42 tan 15

            F_y = 11.25 N

Using the summation of vectors we can find the magnitude of the force applied by the other astronaut is 11.25 N in the y direction

Learn more about vector addition here:

brainly.com/question/15074838

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An object is moving to the west at a constant speed. three forces are exerted on the object. one force is 10 n directed due nort
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If we want the object to continue to move at constant speed, it means that the resultant of the forces acting on the object must be zero. So far, we have:
- force F1 with direction north, of 10 N
- force F2 with direction west, of 10 N
The third force must balance them, in order to have a net force of zero on the object.

The resultant of the two forces F1 and F2 is
F_{12} =  \sqrt{F_1^2+F_2^2}= \sqrt{(10 N)^2+(10 N)^2}= \sqrt{200}=14.1 N
with direction at 45^{\circ} north-west. This means that F3 must be equal and opposite to this force: so, F3 must have magnitude 14.1 N and its direction should be 45^{\circ} south-east.
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3 years ago
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