Answer: d :The blue and orange soccer balls; they have more mass than the black soccer ball, but changed speed by the same amount.
Answer:
1.69×10²⁹ molecules.
Explanation:
The following data were obtained from the question:
Mass of Ammonia (NH3) = 5.25 tons
Molecules of Ammonia (NH3) =.?
Next, we shall convert 5.25 tons to grams (g). This can be obtained as follow:
1 ton = 907184.74 g
Therefore,
5.25 ton = 5.25 ton × 907184.74 g / 1 ton
5.25 ton = 4762719.885 g
Therefore, 5.25 tons is equivalent to 4762719.885 g
Finally, we shall determine the number of molecules of ammonia, NH3 in 4762719.885 g. This can be obtained as follow:
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ molecules. This implies that 1 mole of ammonia, NH3 also contains 6.02×10²³ molecules.
1 mole of ammonia, NH3 = 14 + (3x1) = 14 + 3 = 17 g
17 g of ammonia, NH3 contains 6.02×10²³ molecules.
Therefore, 4762719.885 g of ammonia, NH3 will contain = (4762719.885 × 6.02×10²³) / 17 = 1.69×10²⁹ molecules.
From the calculations made above,
5.25 tons (4762719.885 g) of ammonia, NH3 contains 1.69×10²⁹ molecules.
According to the periodic table, carbon's molar mass is 12.011 grams per mole (that's the small number under the element). So, just multiply like this to get the answer:
So, there are approximately 0.208 grams in 2.5 moles of carbon.
Download the app called Socratic it helps with this
Answer:
Transition temperature = 13 C
Explanation:
ΔS(transition) = 8.8 J/K.mol
ρ(gray) = 5.75 g/cm³ = 5750 kg/m³
ρ(white) = 7.28 g/cm³ = 7280 kg/m³
ΔP = 100 atm = 100 x 101325 = 10132500 Pa
M(Sn) = 118.71g/mol = 118.71 x 10⁻³ kg/mol
T(i) = 18 C, T(f) = ?
We know that
G = H - TS, where G is the gibbs free energy, H is the enthalpy, T is the temperature and S is the entropy
H = V(m) x P, hence the equation becomes
G = V(m) x P - TS
The change in Gibbs free energy going from G(gray) to G(white) = 0 as no change of state takes place hence it can be said that
ΔG(gray) - ΔG(white) = 0
replacing the G with it formula shown above we can arrange the equation such as
0 = V(m)(gray) - V(m)(white) x ΔP - (ΔS(gray) - ΔS(white)) x ΔT
solving for ΔT we get
ΔT = {V(m)(gray) - V(m)(white) x ΔP}/(ΔS(gray) - ΔS(white))
ΔT = {M(Sn)(1/ρ(gray) - 1/ρ(white) x ΔP}/(ΔS(gray) - ΔS(white))
ΔT = {118.71 x 10⁻³ x {(1/5750) - (1/7280)} x 10132500}/(8.8)) = 5.0 C
ΔT = T(initial) - T(transition)
T(transition) = T(initial) - ΔT = 18 - 5 = 13 C
