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GalinKa [24]
3 years ago
9

How does distance between two objects affect their gravitational force? (2 points)

Chemistry
2 answers:
prisoha [69]3 years ago
5 0

Answer:

Option B: as the distance between the objects increases the Force of gravity decreases

Sergio039 [100]3 years ago
4 0
Force is not related to distance
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Which of the following will affect the rate of a chemical reaction?
dimulka [17.4K]

Answer:

Solute concentration will afect the rate of a chemical reaction, because you must work with molarity

Explanation:

I think that solute mass may be it can affect the rate of reaction, if you have more mass in a solute, you will also have more moles.

If you want to know more, you have to consider temperature in the reaction and the  presence of catalysts. They all, affect reactions.

7 0
3 years ago
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Which weather condition can be described as clouds at ground level?
PtichkaEL [24]
A cloud that forms on the ground is called fog. Some clouds you see in the sky might be from airplanes. These are called contrails. High level cirrus clouds may travel at speeds up to 100 mph.
6 0
3 years ago
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Some amount of hydrogen peroxide (H2O2) breaks down to produce 3 molecules of oxygen (O2) and 6 molecules of water (H2O). How ma
soldier1979 [14.2K]

Answer:

Atoms_H=12Atoms

Explanation:

Hello,

In this case, the only source of hydrogen is in the 6 molecules of water, therefore, the atoms of hydrogen, by applying stoichiometry with the Avogadro's number is:

Atoms_H=6moleculesH_2O*\frac{1molH_2O}{6.022x10^{23}moleculesH_2O}\frac{2molH}{1molH_2O}*\frac{6.022x10^{23}AtomsH}{1molH} \\Atoms_H=12Atoms

Best regards.

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3 years ago
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Assume the molality of isoborneol in your product is 0.275 mol/kg. What is the melting point of your impure sample given that th
aliina [53]

Answer:

168°C is the melting point of your impure sample.

Explanation:

Melting point of pure camphor= T =179°C

Melting point of sample = T_f = ?

Depression in freezing point = \Delta T_f

Depression in freezing point  is also given by formula:

\Delta T_f=i\times K_f\times m

K_f = The freezing point depression constant

m = molality of the sample  = 0.275 mol/kg

i = van't Hoff factor

We have: K_f = 40°C kg/mol

i = 1 (  non electrolyte)

\Delta T_f=1\times 40^oC kg/mol\times 0.275 mol/kg

\Delta T_f=11^oC

\Delta T_f=T- T_f

T_f=T- \Delta T_f=179^oC-11^oC=168^oC

168°C is the melting point of your impure sample.

4 0
3 years ago
Find the specific heat of an unknown material with an initial temperature of 20°C, when 5000 Joules are applied to a 50 gram sam
xxTIMURxx [149]

Answer:

2J/g°C

Explanation:

Q = 5000J

Initial temperature (T1) = 20°C

Final temperature (T2) = 70°C

Specific heat capacity (c) = ?

Heat energy (Q) = mc∇T

Q = mc∇T

Q = mc(T2 - T1)

5000 = 50 × c × (70 - 20)

5000 = 50c × 50

5000 = 2500c

c = 5000 / 2500

c = 2J/g°C

The specific heat capacity of the substance is 2J/g°C

8 0
3 years ago
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