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3 years ago

How does distance between two objects affect their gravitational force? (2 points)

Chemistry

2 answers:

prisoha [69]3 years ago

5 0

Answer:

Option B: as the distance between the objects increases the Force of gravity decreases

Sergio039 [100]3 years ago

4 0

Force is not related to distance

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Calculate the amount of heat gained by the water in cup 2 after adding the hot object(s) to it.

Iteru [2.4K]

Answer:

The amount of heat gained by the water in cup 2 after adding the hot object(s) to it is 2119.121 Joules

Explanation:

As we know

Amount of heat gained

Q = mc (T2-T1)

Here,

mass of water in cup 2 (m) = 79.10 grams

Temperature of water in cup 2 = 16.8 degree Celsius

Specific heat of water (c) = 4.186 J/(g °C)

Final Temperature of water in cup 2 = 23.2 degree Celsius

Substituting the given values, we get -

Q = 79.10 * 4.186 * (23.2 -16.8) = 2119.121 Joules

The amount of heat gained by the water in cup 2 after adding the hot object(s) to it is 2119.121 Joules

3 0

3 years ago

Which coefficients correctly balance the formula equation nh4no2(s)® n2(g) + h2o(l)?

Nonamiya [84]

NH4NO2(s)---> N2(g) + 2H2O(l)

8 0

3 years ago

imagine you have four food dyes to test A, B, C and D imagine that you are going to investigate which food dye diffuses more qui

Lady_Fox [76]

Answer:

You will change which food dye is used. You will measure how quickly the dyes diffuse. You could use a timer to see how long the dye takes to completely diffuse.

5 0

3 years ago

Sodium peroxide (Na2O2) is used to remove carbon dioxide from (and add oxygen to) the air supply in spacecrafts. It works by rea

bazaltina [42]

The volume (in liters) of CO₂ that can be consumed at STP by 435 g Na₂O₂ is 125 L of Co₂

calculation

2Na₂O₂(s) +2 CO₂ (g)→ 2 Na₂CO₃(s) + O₂(g)

Step 1 : find the moles of Na₂O₂

moles = mass÷ molar mass

from periodic table the molar mass of Na₂O₂ = (23 x2) +( 16 x2) = 78 g/mol

moles= 435 g÷ 78 g/mol = 5.58 moles

Step 2: use the mole ratio to determine the moles of CO₂

from given equation Na₂O₂ : CO₂ =2 :2 =1:1

Therefore the moles of CO₂ is also = 5.58 moles

Step 3: find the volume of CO₂ at STP

that is at STP 1 mole of a gas = 22.4 L

5.58 moles = ? l

by cross multiplication

= (5.58 moles x 22.4 L) / 1 mole = 125 L

6 0

3 years ago

In a aqueous solution of 4-chlorobutanoic acid , what is the percentage of -chlorobutanoic acid that is dissociated

lord [1]

Answer:

Explanation:

Let assume that the missing aqueous solution of 4-chlorobutanoic acid = 0.76 M

Then, the dissociation of 4-chlorobutanoic acid can be expressed as:

$\mathsf{C_3H_6ClCO_2H }$ ⇄ $\mathsf{C_3H_6ClCO_2^-}$ + $\mathsf{H^+}$

The ICE table can be computed as:

$\mathsf{C_3H_6ClCO_2H }$ ⇄ $\mathsf{C_3H_6ClCO_2^-}$ + $\mathsf{H^+}$

Initial 0.76 - -

Change -x +x +x

Equilibrium 0.76 - x x x

$K_a = \dfrac{[\mathsf{C_3H_6ClCO_2^-}] [\mathsf{H^+}]}{\mathsf{[C_3H_6ClCO_2H ]}}$

$K_a = \dfrac{[x] [x]}{ [0.76-x]}$

where:

$K_a = 3.02*10^{-5}$

$3.02*10^{-5} = \dfrac{x^2}{ [0.76-x]}$

however, the value of x is so negligible:

0.76 -x = 0.76

Then:

$3.02*10^{-5}*0.76 = x^2$

$x=\sqrt{3.02*10^{-5}*0.76 }$

x = 0.00479 M

∴

$x = \mathsf{[C_3H_6ClCO_2^-] = [H^+]=}$ 0.00479 M

$\mathsf{C_3H_6ClCO_2H }$ = (0.76 - 0.00479) M

= 0.75521 M

Finally, the percentage of the acid dissociated is;

= ( 0.00479 / 0.76) × 100

= 0.630 M

7 0

3 years ago