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mote1985 [20]
3 years ago
6

Tech A says that to reassemble a duo-servo brake, first reassemble the brake shoes on the backing plate, and then attach the par

king brake lever on the brake shoes along with the parking brake cable. Tech B says that to reassemble a duo-servo brake, first reassemble the parking brake lever on the brake shoe and parking brake cable, and then mount both brake shoes on the backing plate. Who is correct
Engineering
1 answer:
cupoosta [38]3 years ago
3 0

A duo-servo break makes use of mechanical arrangements to multiply the braking force

The technician that gives the correct procedure of reassembly of duo-servo  brake is Tech B, therefore;

Tech B only is correct

The process by which the above answer is arrived at  

To reassemble a duo-servo brake, the first step is to reassemble on the brake shoe and parking brake cable, the parking brake lever. The star wheel assembly is then reassembled, and set aside after lubricating the floating end. The pads on the backing plate are lubricated and both brake shoes are then installed on the backing plate

Therefore, Tech A states that the brake shoes on the backing plate are reassembled first is not correct, while Tech B is correct

Learn more about duo-servo brake here:

brainly.com/question/13439898

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Explanation:

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An engine operates on gasoline (LHV=44 MJ/kg) with a brake thermal efficiency of 37.9 % What is the brake specific fuel consumpt
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Answer:

s =0.21\ kg/Kw.hr

Explanation:

Given that

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CV= 44,000 KJ/kg

Brake thermal efficiency(η) = 37.9 %

We know that

\eta =\dfrac{BP}{\dot{m_f}\times CV}

Where BP is the brake power

\eta =\dfrac{BP}{\dot{m_f}\times CV}

0.379 =\dfrac{BP}{\dot{m_f}\times 44000}

\dfrac{BP}{\dot{m_f}}=16676

Brake specific fuel consumption (s)

s =\dfrac{\dot{m_f}}{BP}

s =\dfrac{3600\times \dot{m_f}}{BP}

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7 0
3 years ago
Liquid ethanol (C2H5OH) at 298 K, 1 atm enters a steam generator operating at steady state and burns completely with dry air ent
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Answer:

Q= 6491.100 kJ/s

Explanation:

Air-Fuel Ratio:

For a combustion reaction the proportion of air that is present in a gaseous substance responsible for the reaction,this proportion is known as air-fuel ratio.The air fuel ratio is calculated using the combustion reaction for the substance.

Considering reaction for the Ethanol as

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Balancing the equation we get;

a=2,

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xO₂=3

The air-fuel ratio

A/F = XO₂+H₂O+xN₂× mass of N₂/mass(fuel)

3.31×31.9+11.28×28.013/46.069

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Equivalent ratio = 0.7,

so, heat transfer

Q= m ×Cp×ΔT

= 75×0.7×112.4(1500-400)

Q= 6491.100 kJ/s

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∴ Q= 6491100 W

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6 0
4 years ago
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