To fully understand the problem, we use the ICE table to identify the concentration of the species. We calculate as follows:
Ka = 2.0 x 10^-9 = [H+][OBr-] / [HOBr]
HOBr = 0.50 M
KOBr = 0.30 M = OBr-
<span> HOBr + H2O <-> H+ + OBr- </span>
<span>I 0.50 - 0 0.30 </span>
<span>C -x x x
</span>---------------------------------------------
<span>E(0.50-x) x (0.30+x) </span>
<span>Assuming that the value of x is small as compared to 0.30 and 0.50 </span>
<span>Ka = 2.0 x 10^-9 = x (0.30) / 0.50) </span>
<span>x = 3.33 x 10^-9 = H+</span>
pH = 8.48
Answer:
The answer to your question is 64.02 g of H₂O
Explanation:
Data
Mass of magnesium sulfate hepta hydrated = 125 g
Mass of water = ?
Process
1.- Calculate the molar mass of the salt and the molar mass of water
molar mass of MgSO₄ 7H₂O = 24 + 32 + 64 + 14 + 112 = 246 g
mass of H₂O = 2 + 16 = 18 g
2.- Use proportions to calculate the mass of water in the epsom salt
246 g MgSO₄ 7H₂O------------------------- 126 g of H₂O
125 g ------------------------- x
x = (125 x 126)/246
x = 15750/246
x = 64.02 g of H₂O
Answer:
1859.4 g of ZnCrO₄ in 10.25 moles
Explanation:
First of all, we determine the molecular formula of the compound:
Zinc → Zn²⁺ (cation)
Chromate → CrO₄⁻² (anion)
Zinc chromate → ZnCrO₄
Molar mass for the compound is:
Molar mass of Zn + Molar mass of Cr + (Molar mass of O) . 4 = 181.41 g/mol
65.41 g/mol + 52 g/mol + 16 g/mol . 4 = 181.41 g/mol
Let's apply this conversion factor: 10.25 mol . 181.41 g/mol = 1859.4 g
Answer:
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Explanation:
Dissolving 0.729 mol NaCl in 2530 mL of water yields a solution with 2.88M concentration.
Explanation:
The moles of NaCl given will be dissolved and volume will be made with given data will give molarity.
The units for molarity are moles/litre, so the volume given in ml will be converted to litres by dividing it with 1000.
data given:
number of moles of NaCl = 0.729 moles
volume of the solution = 2530 ml or 2.53 litre
To calculate the concentration of the solution the formula used is:
molarity = 
= 0.288 M
The concentration or molarity of the solution OF NaCl is 2.88M
