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pychu [463]
3 years ago
13

Explain why the enthalpies of vaporization of the following substances increase in the order CH4 < NH3 < H2O, even though

all three substances have approximately the same molar mass.
Chemistry
1 answer:
stich3 [128]3 years ago
5 0

Explanation:

More is the intermolecular forces present between the molecules of a substance more will be the boiling point of the substance.

Since, water is able to form hydrogen bonding and it also have dipole-dipole interaction as these are stronger than the forces present in ammonia. Hence, boiling point of water is greater than the boiling point of NH_{3}.

In CH_{4}, there are only dispersion forces present in it and these forces are weakest intermolecular forces.

As a result, the enthalpies of vaporization of the following substances increase in the order CH_{4} < NH_{3} < H_{2}O.

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What is the formula weight (amu) of the molecule H2O? Use atomic masses of H and O as 1.008 amu and 16.00 amu respectively. Repo
vaieri [72.5K]

Answer:

Formula weight of H₂O molecule is  18.02 amu.

Explanation:

Given data:

Formula weight of H₂O = ?

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Solution:

Formula weight:

"It is the sum of all the atomic weight of atoms present in given formula"

Formula weight of H₂O = 2×1.008 amu + 1×16.00 amu

Formula weight of H₂O = 18.02 amu

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Help me with this please!
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The correct answer is 9.7 grams because mg are 1,000 difference to grams.

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