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3 years ago

Pete walks at a rate of 4.0 miles per hour for 30 minutes. How far did he walk?

1 answer:

3 0

2 miles i believe because if he walks at 4.0 miles an hour divided by that 30 minutes basically just splitting it in half giving you 2 miles

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There are four charges, each with a magnitude of 1.96 µC. Two are positive and two are negative. The charges are fixed to the co

mart [117]

Answer:

Magnitude of the resultant force (Fn₁) on q₁

Fn₁ = 0.142N (directed toward the center of the square)

Explanation:

Theory of electrical forces

Because the particle q₁ is close to three other electrically charged particles, it will experience three electrical forces and the solution of the problem is of a vector nature.

Graphic attached

The directions of the individual forces exerted by q₂, q₃ and q₄ on q₁ are shown in the attached figure.

The force (F₁₄) of q₄ on q₁ is repulsive because the charges have equal signs and the forces (F₁₂) and (F₁₃) of q₂ and q₃ on q₁ are attractive because the charges have opposite signs.

Calculation of the forces exerted on the charge q₁

To calculate the magnitudes of the forces exerted by the charges q₂, q₃, and q₄ on the charge q₁ we apply Coulomb's law:

$F_{12} = \frac{k*q_1*q_2}{r_{12}^2}$ : Magnitude of the electrical force of q₂ over q₁. Equation((1)

$F_{13} = \frac{k*q_1*q_3}{r_{13}^2}$ : Magnitude of the electrical force of q₃ over q₁. Equation (2)

$F_{14} = \frac{k*q_1*q_4}{r_{14}^2}$ : Magnitude of the electrical force of q₄ over q₁. Equation (3)

Equivalences

1µC= 10⁻⁶ C

Known data

q₁=q₄= 1.96 µC = 1.96*10⁻⁶C

q₂=q₃= -1.96 µC = -1.96*10⁻⁶C

r₁₂= r₁₃ = 0.47m: distance between q₁ and q₂ and q₁ and q₄

$r_{14} = \sqrt{0.47^2+ 0.47^2}=0.664m$

k=8.99x10⁹N*m²/C² : Coulomb constant

F₁₂ calculation

We replace data in the equation (1):

$F_{12} = \frac{8.99*10^9*(1.96*10^{-6})^2}{0.47^2}$

F₁₂ = 0.156 N Direction of the positive x axis (+x)

F₁₃ calculation

We replace data in the equation (2):

$F_{13} = \frac{8.99*10^9*(1.96*10^{-6})^2}{0.47^2}$

F₁₃ = 0.156 N Direction of the negative y axis (-y)

Magnitude of the net electrostatic force between F₁₃ and F₁₂

$F_{n23}= \sqrt{0.156^2+0.156^2} = 0.22N$ (directed toward the center of the square)

F₁₄ calculation

We replace F₁₄ data in the equation (3):

$F_{14} = \frac{8.99*10^9*(1.96*10^{-6})^2}{0.664^2}$

F₁₄ = 0.078 N (In the opposite direction to Fn₂₃)

Calculation of the resulting force on q₁: Fn₁

Fn₁ = Fn₂₃ - F₁₄ = 0.22 - 0.078 = 0.142 N

6 0

3 years ago

Why did fundamentalists feel threatened by new scientific knowledge?

Kamila [148]

Because the fundamentalist interprets scriptures of the religion literally so new scientific knowledge has proven some of the events that happened in scriptures, that no one can comprehend in the old times. and the fundamentalist feel threatened because there are some of their beliefs are now contradicting
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7 0

3 years ago

A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle

aalyn [17]

Answer:

4.56 s

Explanation:

Let t (seconds) be the time it takes from the moment when the motorcycle starts to accelerate until it catches up with the car. Since prior to this they are traveling at constant speed, they would have maintained a distance of 52 m before accelerating.

The distance traveled by the car, with respect the motorcycle position when it start accelerating is

$s_c = s_0 + v_ct = 52 + 19t$