A sinewave has a period (duration of one cycle) of 645 μs (microseconds). What is the corresponding frequency of this sinewave,

Question

3 years ago

5

in kHz

1 answer:

Oliga [24] · Answer 1 · 2022-10-17T00:36:29+03:00

The corresponding frequency of this sinewave, in kHz, expressed to 3 significant figures is: 155 kHz.

Given the following data:

Note: μs represents microseconds.

Conversion:

1 μs = $1$ × $10^-6$ seconds

645 μs = $645$ × $10^-6$ seconds

To find corresponding frequency of this sinewave, in kHz;

Mathematically, the frequency of a waveform is calculated by using the formula;

$Frequency = \frac{1}{Period}$

Substituting the value into the formula, we have;

$Frequency = \frac{1}{645 * 10^-6}$

Frequency = 1550.39 Hz

Next, we would convert the value of frequency in hertz (Hz) to Kilohertz (kHz);

Conversion:

1 hertz = 0.001 kilohertz

1550.39 hertz = X kilohertz

Cross-multiplying, we have;

X = $0.001$ × $1550.39$

X = 155039 kHz

To 3 significant figures;

Frequency = 155 kHz

Therefore, the corresponding frequency of this sinewave, in kHz is 155.