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GenaCL600 [577]
3 years ago
9

Do cheese and chips good?

Physics
2 answers:
Luda [366]3 years ago
7 0
They good good smack, nachos, cheesy chips, chips and quest, cheese and chips ( ˘ω˘ )
Please mark brainliest my good cheesy sire
olga_2 [115]3 years ago
6 0

Answer:

YES VERY GOOD

Explanation:

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A two-liter bottle of your favorite beverage has just been removed from the trunk of your car. The temperature of the beverage i
Ksivusya [100]

Answer:

a) 209.3 kilojoules must be removed from two liter of beverage, b) A rate of heat removal of 1.163 kilowatts is required to cool down 10 2-liter bottles, c) Cooling 10 2-L bottles during 30 minutes costs 4.9 cents.

Explanation:

a) <em>How much heat energy must be removed from your two liters of beverage?</em>

At first we suppose that the beverage has the mass and specific heat of water and that there are no energy interactions between the bottle and its surroundings.

From the First Law of Thermodynamics and definition of sensible heat, we get that amount of removed heat (Q), measured in kilojoules, is represented by the following formula:

Q = \rho \cdot V\cdot c\cdot (T_{o}-T_{f}) (Eq. 1)

Where:

\rho - Density of the beverage, measured in kilograms per cubic meter.

V - Volume of the bottle, measured in cubic meters.

c - Specific heat of water, measured in kilojoules per kilogram-Celsius.

T_{o}, T_{f} - Initial and final temperatures, measured in Celsius.

If we know that \rho = 1000\,\frac{kg}{m^{3}}, V = 2\times 10^{-3}\,m^{3}, c = 4.186\,\frac{kJ}{kg\cdot ^{\circ}C}, T_{o} = 35\,^{\circ}C and T_{f} = 10\,^{\circ}C, then:

Q = \left(1000\,\frac{kg}{m^{3}}\right)\cdot (2\times 10^{-3}\,m^{3})\cdot \left(4.186\,\frac{kJ}{kg\cdot ^{\circ}C} \right) \cdot (35\,^{\circ}C-10\,^{\circ}C)

Q = 209.3\,kJ

209.3 kilojoules must be removed from two liter of beverage.

b) <em>You are having a party and need to cool 10 of these two-liter bottles in one-half hour. What rate of heat removal, in kW, is required?</em>

The total amount of heat that must be removed from 10 2-L bottles is:

Q_{T} = 10\cdot (209.3\,kJ)

Q_{T} = 2093\,kJ

If we suppose that bottles are cooled at constant rate, then, rate of heat removal is determined by this formula:

\dot Q = \frac{Q_{T}}{\Delta t} (Eq. 2)

Where:

Q_{T} - Total heat, measured in kilojoules.

\Delta t - Time, measured in seconds.

\dot Q - Rate of heat removal, measured in kilowatts.

If we know that Q_{T} = 2093\,kJ and \Delta t = 1800\,s, we find that rate of heat removal is:

\dot Q = \frac{2093\,kJ}{1800\,s}

\dot Q = 1.163\,kW

A rate of heat removal of 1.163 kilowatts is required to cool down 10 2-liter bottles.

c) <em>Assuming that your refrigerator can accomplish this and that electricity costs 8.5 cents per kW-hr, how much will it cost to cool these 10 bottles (in $)?</em>

A kilowatt-hour equals 3600 kilojoules. The electricity cost is equal to the  removal heat of 10 bottles (Q_{T}), measured in kilojoules, and unit electricity cost (c), measured in US dollars per kilowatt-hour. That is:

C = c\cdot Q_{T}

If we know that c = 0.085\,\frac{USD}{kWh} and Q_{T} = 2093\,kJ, the total cost of cooling 10 bottles is:

C = \left(0.085\,\frac{USD}{kWh}\right)\cdot \left(2093\,kJ\right)\cdot \left(\frac{1}{3600}\,\frac{kWh}{kJ}  \right)

C = 0.049\,USD

Cooling 10 2-L bottles during 30 minutes costs 4.9 cents.

3 0
4 years ago
The product of 14 and a cubed
olya-2409 [2.1K]

Answer:

14 × a^3

Explanation:

Product means multiplication

Cubed means to the power of 3

6 0
4 years ago
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I WILL CHOOSE YOU AS THE BRAINIEST PLEASE ANSWER MY QUESTION
Brilliant_brown [7]

Answer:

It's like the Earth pulling on you and keeping you on the ground. That pull is gravity at work. Every object in the universe that has mass exerts a gravitational pull, or force, on every other mass. The size of the pull depends on the masses of the objects.

Explanation:

5 0
4 years ago
1. At a location in Europe, it is necessary to supply 1000 kW of 60-Hz power. Only power sources available operate at 50 Hz. It
Klio2033 [76]

Answer:

Explanation:

From the given information:

The speed of a synchronous motor in relation to its frequency can be represented with the formula:

n_{sm}= \dfrac{120f_{se}}{P}

where,

the electrical frequency f_{se} is measured in Hz

the number of poles = P

For us to estimate the number of poles to have 50 Hz - 60 Hz Power, then we need to relate the frequencies of the above equation.

i.e

\dfrac{120(50 \ Hz)}{P_1}= \dfrac{120( 60 \Hz)}{P_2} \\ \\ \dfrac{6000 \ Hz}{P_1}= \dfrac{7200 \ Hz}{P_2} \\ \\ \dfrac{P_2}{P_1}=\dfrac{7200}{6000} \\ \\ \\ \dfrac{P_2}{P_1}= \dfrac{12}{10}

Thus, we can conclude that 10 poles synchronous motor is attached with 12 poles synchronous generator in order to convert 50 Hz to 60 Hz power.

3 0
3 years ago
You see the moon rising, just as the sun is setting. What phase is the moon in?.
Readme [11.4K]

Answer:

full phase

Explanation:

sorry if its wrong

4 0
2 years ago
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