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2 years ago

Do cheese and chips good?

2 answers:

7 0

They good good smack, nachos, cheesy chips, chips and quest, cheese and chips ( ˘ω˘ )
Please mark brainliest my good cheesy sire

olga_2 [115]2 years ago

6 0

Answer:

YES VERY GOOD

Explanation:

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A dog walking to the right at 1.5\,\dfrac{\text m}{\text s}1.5sm1, point, 5, space, start fraction, m, divided by, s, end fract

Tatiana [17]

Answer:

8.6 m/s

Explanation:

We can find the final velocity of the dog by using the following SUVAT equation:

$v^2-u^2=2ad$

where

u is the initial velocity

a is the acceleration

d is the distance covered

For the dog in the problem, we have

u = 1.5 m/s

$a = 12 m/s^2$

And the distance covered is

d = 3.0 m

Therefore, we can re-arrange the equation to find the final velocity, v:

$v=\sqrt{u^2+2ad}=\sqrt{1.5^2+2(12)(3.0)}=8.6 m/s$

6 0

2 years ago

Name some elements that have a symbol that is entirely different from the spelling of the world

Alenkasestr [34]

Some elements that have a symbol entirely different from the spelling are..

1.Fe. Iron
2.Na.Sodium
3.K. Pottasium
4.Ag.Silver
5.Sn.Tin
6.Sb. Antimony
7,Pb.Lead

7 0

2 years ago

A liquid thermometer can be used to test for fevers. When body temperature increases, the liquid inside the thermometer expands

kompoz [17]

Answer:

Explanation:

dafdfsfsf

4 0

3 years ago

A 22 µF capacitor charged to 0.7 kV and a second 115 µF capacitor charged to 5.5 kV are connected to each other, with the positi

vesna_86 [32]

Answer:

0.099C

Explanation:

First, we need to get the common potential voltage using the formula

$V=\frac {C_2V_2-C_1V_1}{C_1+C_2}$

Where V is the common voltage, C and V represent capacitance and charge respectively. Subscripts 1 and 2 to represent the the first and second respectively. Substituting the above with the following given values then

$C_1=22\times 10^{-6} F\\ C_2=115\times 10^{-6} F\\ V_1= 0.7\times 10^{3}\\V_2=5.5\times 10^{3}$

Therefore

$V=\frac {115\times 10^{-6}\times 5.5\times 10^{3}-22\times 10^{6}\times 0.7\times 10^{3}}{22\times 10^{-6}+115\times 10^{-6}}=4504.3795620437$

Charge, Q is given by CV hence for the first capacitor charge will be $Q_1=C_1V$

Here, $Q_1=22\times 10^{-6}\times 4504.3795620437=0.0990963503649C\approx 0.099C$

8 0

3 years ago

Calculate the east component of a resultant 32.5 m/s, 35.0° east of north.

ValentinkaMS [17]

Answer:

East component is: 18.64 m/s

Explanation:

If the resultant is 32.5 m/s directed 35 degrees east of north, then we use the sin(35) projection to find the east component of the velocity:

East component = 32.5 m/s * sin(35) = 18.64 m/s

4 0

2 years ago