(1500 rev/min)(min / 60 s) / (3.0 s) = 8.33 rev/s²
<span>(B) </span>
<span>(1/2)(8.33 rev/s²)(3.0 s)² = 37.5 rev </span>
<span>(C) </span>
<span>(1500 rev/min)(min / 60 s)[2π(0.12 m) / rev] = 18.8 m/s</span>
Answer:
The environment is warmed by the light throughout the day, such that the temperature increases. The weather is decreasing and the temperature decreases in the night as the sun falls. There was a misunderstanding. Thanks to the density, the atmosphere becomes densest on the earth. The air becomes colder and colder when you move up.
Explanation:
Answer is above
<em><u>Hope this helps.</u></em>
Answer:
v = 21.03 m/s
Explanation:
given,
mass of skier = 45 kg
the slope of the snow = 10.0◦
coefficient of friction = 0.114
distance traveled = 300 m
speed = ?
Acceleration = g sin θ - µ g Cos θ
= 9.8 × Sin (10°) - 0.10 × 9.8 × Cos(10°)
= 0.737 m/s²
using equation of motion
v² = u² + 2 a s
v² = 0 + 2 × 0.737 × 300
v = 21.03 m/s
Speed of skier's after travelling 300 m speed is equal to 21.03 m/s
The moon has a small amount of gravity. Low tides mean the moon is not pulling on the water. High tides mean that the moon is pulling on the water.
Use KE= 1/2mv^2
So...
50,000=(.5)(1,000)v^2
50,000=500 x v^2
Divide 500 on both sides
100 = v^2
Square root both sides to get rid of v^2
Therefore v = 10 m/s
