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salantis [7]
2 years ago
11

Marty is developing a new way to heat an airplane's windshield to prevent it from accumulating ice when in flight. A thin layer

of clear, conductive material is injected between two layers of thick windshield plastic. A very small electric current is run through the inner material to keep the plastic layers warm. How might using a model help Marty develop his design? A. Marty could use a model to discover a new type of plastic for windshields. B. Airplane manufacturers could be sold models to use in their new planes. C. A model could be used to test his design in a lab. D. A model could be used for automobile windshields.
Physics
2 answers:
Snezhnost [94]2 years ago
8 0
The answer is : <span>A model could be used to test his design in a lab.  </span>Marty is developing a new way to heat an airplane's windshield to prevent it from accumulating ice when in flight. A thin layer of clear, conductive material is injected between two layers of thick windshield plastic. A very small electric current is run through the inner material to keep the plastic layers warm.  The model that could help Marty develop his design is the kind of model that could be used to test his design in a lab. 
stich3 [128]2 years ago
3 0

Answer:

B) A model could be used to test his design in a lab

Explanation:

The models in a laboratory scale are used usually to  test new methods or technologies (like the one Marty is developing) to see if they work or what adjustments they required to take them to real scale.

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Which product forms from the synthesis reaction between calcium (Ca) and
cestrela7 [59]

Answer:

CaCl2

Explanation:

5 0
2 years ago
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A 20-kg block is held at rest on the inclined slope by a peg. A 2-kg pendulum starts at rest in a horizontal position when it is
gregori [183]

Complete Question

The diagram of this question is shown on the first uploaded image

Answer:

The distance the block slides before stopping is d = 0.313 \ m

Explanation:

The free body diagram for the diagram in the question is shown

From the diagram the angle is \theta = 25 ^o

         sin \theta  = \frac{h}{d}

Where h = h_b - h_a

     So      d sin \theta  = h_b - h_a

From the question we are told that

      The mass of the block is  m = 20 \ kg

       The mass of the pendulum is  m_p = 2 \ kg

       The velocity of the pendulum at the bottom of swing is v_p = 15 m/s

        The coefficient of restitution is  e =0.7

         The coefficient of kinetic friction is  \mu _k = 0.5

The velocity of the block after the impact is mathematically represented as

            v_2 f = \frac{m_b - em_p}{m_b + m_p}  * v_2 i + \frac{[1 + e] m_1}{m_1 + m_2 } v_p

Where  v_2 i is the velocity of the block  before collision which is  0

                  = \frac{20 - (0.7 * 2)}{(2 + 20)} * 0 + \frac{(1 + 0.7) * 2 }{2 + 20}   * 15

Substituting value

                   v_2 f = 2.310\  m/s

According to conservation of energy principle

      The energy at point a  =  energy at point b

So    PE_A + KE _A = PE_B + KE_B  +  E_F

Where  

         PE_A is the potential energy at A which is mathematically represented as

          PE_A = m_b gh_a = 0 at the bottom

      KE _A is the kinetic energy at A  which is mathematically represented as

               K_A = \frac{1}{2} m_b * v_2f^2                  

         PE_B is the potential energy at B which is mathematically represented as  

            PE_B = m_b gh

From the diagram h = h_b -h_a

       PE_B = m_b g(h_b - h_a)

KE _B is the kinetic energy at B  which is 0 (at the top )

Where is E_F is the workdone against velocity  which from the diagram is

      \mu_k m_b g cos 25 *d

So

   \frac{1}{2} m_b v_2 f^2  = m_b g h_b + \mu_k m_b g cos \25 * d

Substituting values

   \frac{1}{2}  * 20 * 2.310^2 = 20 * 9.8 * d sin(25)  + 0.5* 20 * 9.8 * cos 25 * d    

So

       d = 0.313 \ m

       

   

6 0
3 years ago
HURRY PLEASE!!!
REY [17]
90for each walk because 6• 15 = 90
8 0
3 years ago
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I am pretty sure its the last one.
CaHeK987 [17]
The answer is has no moons. Mars has two moons
4 0
3 years ago
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An object is moving to the west at a constant speed. three forces are exerted on the object. one force is 10 n directed due nort
SVETLANKA909090 [29]
If we want the object to continue to move at constant speed, it means that the resultant of the forces acting on the object must be zero. So far, we have:
- force F1 with direction north, of 10 N
- force F2 with direction west, of 10 N
The third force must balance them, in order to have a net force of zero on the object.

The resultant of the two forces F1 and F2 is
F_{12} =  \sqrt{F_1^2+F_2^2}= \sqrt{(10 N)^2+(10 N)^2}= \sqrt{200}=14.1 N
with direction at 45^{\circ} north-west. This means that F3 must be equal and opposite to this force: so, F3 must have magnitude 14.1 N and its direction should be 45^{\circ} south-east.
6 0
3 years ago
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