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salantis [7]
3 years ago
11

Marty is developing a new way to heat an airplane's windshield to prevent it from accumulating ice when in flight. A thin layer

of clear, conductive material is injected between two layers of thick windshield plastic. A very small electric current is run through the inner material to keep the plastic layers warm. How might using a model help Marty develop his design? A. Marty could use a model to discover a new type of plastic for windshields. B. Airplane manufacturers could be sold models to use in their new planes. C. A model could be used to test his design in a lab. D. A model could be used for automobile windshields.
Physics
2 answers:
Snezhnost [94]3 years ago
8 0
The answer is : <span>A model could be used to test his design in a lab.  </span>Marty is developing a new way to heat an airplane's windshield to prevent it from accumulating ice when in flight. A thin layer of clear, conductive material is injected between two layers of thick windshield plastic. A very small electric current is run through the inner material to keep the plastic layers warm.  The model that could help Marty develop his design is the kind of model that could be used to test his design in a lab. 
stich3 [128]3 years ago
3 0

Answer:

B) A model could be used to test his design in a lab

Explanation:

The models in a laboratory scale are used usually to  test new methods or technologies (like the one Marty is developing) to see if they work or what adjustments they required to take them to real scale.

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A merry-go-round accelerating uniformly from rest achieves itsoperating speed of 2.5rpm in five revolution.
g100num [7]

Answer:

(A) The magnitude of its angular acceleration 1.09 x 10⁻³ rad/s²

(B) Time of motion 240.2 s

Explanation:

Given;

final angular speed, ωf = 2.5 RPM

angular distance, θ = 5 rev = 5 x 2π = 10π rad

initial angular speed, ωi = 0

final angular speed in rad/s;

\omega_f = \frac{2.5 \ rev}{min} \times \ \frac{2\pi}{1 \ rev} \times \ \frac{1 \min}{60 s} = 0.2618 \ rad/s \\

(A) the magnitude of its angular acceleration(rad/s^2);

\omega_f^2 = \omega_i^2 + 2\alpha \theta\\\\(0.2618)^2 = 0 + (2\times 10\pi)\alpha\\\\0.0685 = 20\pi \alpha\\\\\alpha = \frac{0.0685}{20\pi} \\\\\alpha = 1.09\times 10^{-3} \ rad/s^2

(B) Time of motion;

\omega_f = \omega_i + \alpha t\\\\0.2618 = 0 + 1.09\times 10^{-3} t\\\\t = \frac{0.2618}{1.09\times 10^{-3}} \\\\t = 240.2 \ s

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3 years ago
How high will a ball go if thrown at 10m/s up?
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4 0
3 years ago
A car is moved 26km/hr due east for 4minute.what is its average velocity in m/s?​
fenix001 [56]

Answer:

25m/sec

Explanation:

Speed of car in first 15 minutes = 40 km/h

Distance covered = speed × Time taken

60 minutes = 1 hour

15 minutes =

60

15

hour

Distance covered = 240×

60

15

=10km

Speed of car in next 15 minutes = 60 km/h

Distance covered = 60×

60

15

=15km

∴ Total distance covered = (10+15)km = 25 km

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3 years ago
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Readme [11.4K]

Answer:

The second one is the answer

7 0
3 years ago
Formula to calculate the weight and mass of a body​
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weight = mass*g is the formula

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