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salantis [7]
3 years ago
11

Marty is developing a new way to heat an airplane's windshield to prevent it from accumulating ice when in flight. A thin layer

of clear, conductive material is injected between two layers of thick windshield plastic. A very small electric current is run through the inner material to keep the plastic layers warm. How might using a model help Marty develop his design? A. Marty could use a model to discover a new type of plastic for windshields. B. Airplane manufacturers could be sold models to use in their new planes. C. A model could be used to test his design in a lab. D. A model could be used for automobile windshields.
Physics
2 answers:
Snezhnost [94]3 years ago
8 0
The answer is : <span>A model could be used to test his design in a lab.  </span>Marty is developing a new way to heat an airplane's windshield to prevent it from accumulating ice when in flight. A thin layer of clear, conductive material is injected between two layers of thick windshield plastic. A very small electric current is run through the inner material to keep the plastic layers warm.  The model that could help Marty develop his design is the kind of model that could be used to test his design in a lab. 
stich3 [128]3 years ago
3 0

Answer:

B) A model could be used to test his design in a lab

Explanation:

The models in a laboratory scale are used usually to  test new methods or technologies (like the one Marty is developing) to see if they work or what adjustments they required to take them to real scale.

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In a butcher shop, a horizontal steel bar of mass 4.94 kg and length 1.46 m is supported by two vertical wires attached to its e
mojhsa [17]

Answer:

Tension in right wire = 25.9N

Explanation:

I have attached a free body diagram to depict this question.

From the diagram, i have labelled the tensions in the strings T1 and T2.

While i labelled the weight of the bar as Wb and weight of sausage as Ws.

Now, when solving a problem like this we want to first remember that the beam is static; meaning it is not moving. From simple physics, this means that the sum of the forces in the y direction equals zero (i.e. the total downward forces equal the total upward forces)

Thus, from the diagram, the upward forces are T1 and T2 while the downward forces are Ws and Wb.

Thus;

T1 + T2 = Wb + Ws

We know that mass of bar = 4.94kg. Thus, Weight of bar(Wb) = mg = 4.94 x 9.81 = 48.46N

Also, weight of sausage (Ws) = mg = 2.49 x 9.81 = 24.43N

Thus,

T1 + T2 = 48.46N + 24.43

T1 + T2 = 72.89N - - - - - (eq 1)

Now, let's take moments about the left end of the bar.

The maximum weight of the bar will act at the centre, so distance from the Wb to left end = 1.46/2 = 0.73m

So, moments about left end;

T2 x 1.46 = (Wb x 0.73) + (Ws x 0.1)

1.46T2 = (48.46 x 0.73) + (24.43 x 0.1)

1.46T2 = 35.373 + 2.443

1.46T2 = 37.816

T2 = 37.816/1.46 = 25.9N

3 0
3 years ago
How do you know the earth is rotating on its axis
cupoosta [38]

Answer:

Read below!

Explanation:

You can watch the sun wheel across the sky during the day, and the stars at night. Focus a telescope on any star besides the north star--especially southern stars--and you can watch them drift across your field of view.  

An alternative explanation is that all the stars are painted on (or holes in) some canopy that rotates around the earth. This explanation does not account for the motion of the "wanderers," or planets, as the Greeks called them, or for the path of the moon among the stars.  

As we know the stars are massive bodies of significant and varying distance to the earth, the notion they all swing around us in unison seems highly implausible

4 0
3 years ago
A horse has an acceleration of 2 m/s2. If it starts from rest, how fast is it going after 1.7 seconds?
fgiga [73]

       (2  m/s²)  ·  (1.7  s)  =  3.4 m/s
6 0
3 years ago
Read 2 more answers
The circuits, P and Q, show two different ammeter-voltmeter methods of measuring resistance. Suppose the ammeter has a resistanc
qaws [65]

Answer:

Uncorrected values for

For circuit P

R = 2.4 ohm

For circuit Q

R = 2.4 ohm

Corrected values

for circuit P

R = 12 OHM

For circuit Q

R = 2.3 ohm

Explanation:

Given data:

Ammeter resistance 0.10 ohms

Resister resistance 3.0 ohms

Voltmeter read 6 volts

ammeter reads 2.5 amp

UNCORRECTED VALUES FOR

1) circuit P

we know that IR =V

R = \frac{6}{2.5} - 2.4 ohm

2) circuit Q

R = 2.4 ohm as no potential drop across ammeter

CORRECTED VALUES FOR

1) circuit p

IR = V

\frac{3R}{R+3} \times 2.5 = 6

R= 12 ohm

2) circuit Q

I\times (R+0.1) =V

R+0.1 =\frac{6}{2.5}

R = 2.3 ohm

5 0
3 years ago
Which of the following substances could be heated from 20°C to 100°C most quickly? Assume identical heat sources are used on all
Lera25 [3.4K]
Hello There!

Your answer is Gold because it has the lowest SH

Hope This Helps You!
Good Luck :) 

- Hannah ❤
3 0
3 years ago
Read 2 more answers
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