Answer:
(A) The magnitude of its angular acceleration 1.09 x 10⁻³ rad/s²
(B) Time of motion 240.2 s
Explanation:
Given;
final angular speed, ωf = 2.5 RPM
angular distance, θ = 5 rev = 5 x 2π = 10π rad
initial angular speed, ωi = 0
final angular speed in rad/s;

(A) the magnitude of its angular acceleration(rad/s^2);

(B) Time of motion;

And physics and physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsvand physicsand physicsand physicsand physicsand physicsand physicsand physicsvvand physicsand physicsand physicsand physicsvvand physicsand physicsvand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physics
Answer:
25m/sec
Explanation:
Speed of car in first 15 minutes = 40 km/h
Distance covered = speed × Time taken
60 minutes = 1 hour
15 minutes =
60
15
hour
Distance covered = 240×
60
15
=10km
Speed of car in next 15 minutes = 60 km/h
Distance covered = 60×
60
15
=15km
∴ Total distance covered = (10+15)km = 25 km
Answer:
The second one is the answer
weight = mass*g is the formula