Answer:
The magnitude of the torque is 263.5 N.
Explanation:
Given that,
Applied force = 31 N
Distance from the axis = 8.5 m
She applies her force perpendicularly to a line drawn from the axis of rotation
So, The angle is 90°
We need to calculate the torque
Using formula of torque
Where, F = force
d = distance
Put the value into the formula
Hence, The magnitude of the torque is 263.5 N.
Martian water may contain salts, which lowers the freezing temperatures of the water
How is Mars atmosphere?
The atmosphere of Mars is much thinner than Earth’s. The Red Planet's atmosphere contains more than 95% carbon dioxide and much less than 1% oxygen. People would not be able to breathe the air on Mars.
It is possible that liquid water could also exist on the surface of Mars through the formation of brines suggested by the abundance of hydrated salts. Brines are significant on Mars because they can stabilize liquid water at lower temperatures than pure water on its own.
Thus, in the extreme and uneventful conditions of saturation by mixtures of salts, liquid water can be stable on Mars between 180 K and at least up to 298 K.
learn more about Mars from here: brainly.com/question/28197278
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Answer:
ans 5
Explanation:
hope it's help It seems to me
Answer: The reason for the differences in density is the composition of rock in the plates. When two plates come in contact with each other through plate tectonics, scientists can use the density of the plates to predict what will happen. Whichever plate is more dense will sink, and the less dense plate will float over it.
Explanation:
Hope this helps ( not copied and pasted, this answer was done by me so I don't know if it's good or not)
Answer:
Charge stored after insertion will be
Explanation:
We have given potential difference V =2.63 V
charge stored by the capacitor when without dielectric =
We know that , here is capacitance without dielectric
We have given
k = dielectric constant = 5.99
C = Capacitance with the dielectric = k = 3.55× =
Potential difference is due to the external charging source so it remains same
V = potential difference after insertion = 2.63 volts
New charge stored ,