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taurus [48]
2 years ago
10

1. An MR-2 starts from rest and accelerates westward to a speed of 27 m/s in

Physics
1 answer:
dangina [55]2 years ago
8 0

Answer:

a) 2.28 m/s²

b) 159.86 m

Explanation:

<u>Part A:</u>

u = 0 m/s

v = 27 m/s

t = 11.8 seconds

a = ?

<u>Formula:</u>

v = u + at

=> 27 = 0 + a(11.8)

=> 27 = a(11.8)

=> a(11.8) = 27

=> a = 27/11.8

=> a = 2.28 m/s²

<u>Part B:</u>

s = ?

<u>Formula:</u>

s = (v² - u²)/2a

s = (27² - 0²) /2(2.28)

  = 729/4.56

  = 159.86 m

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2 years ago
You obtain a 100-W light bulb and a 50-W light bulb. Instead of connecting them in the normal way, you devise a circuit that pla
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Answer:

When they are connected in series

     The  50 W bulb glow more than the 100 W bulb

Explanation:

From the question we are told that

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Generally the power rating of the first bulb is mathematically represented as

      P_1  =  V^2 R

Where  V is the normal household voltage which is constant for both bulbs

  So  

        R_1  =  \frac{V^2}{P_1 }

substituting values

        R_1  =  \frac{V^2}{100}

Thus the resistance of the second bulb would be evaluated as

       R_2  =  \frac{V^2}{50}

From the above calculation we see that

        R_2  >  R_1

This power rating of the first bulb can also be represented mathematically as  

        P_  1  =  I^2_1  R_1

This power rating of the first bulb can also be represented mathematically as    

       P_  2  =  I^2_2 R_2

Now given that they are connected in series which implies that the same current flow through them so

       I_1^2 =  I_2^2

This means  that

       P \ \alpha  \  R

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3 years ago
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If an object is propelled upward from a height of 128 feet at an initial velocity of 112 feet per​ second, then its height h aft
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Explanation:

The equation of motion of an object is given by :

h(t)=-16t^2+112t+128

Where

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So,

-16t^2+112t+128=0

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3 years ago
1. A large ball was let go on a hill and started rolling down with a constant acceleration of 4.2 m/s². What was the velocity of
pochemuha

Answer:

<em>The velocity after 12s is 50.4m/s</em>.

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