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Ghella [55]
3 years ago
15

Calculate Vector component in Y if the hypotenuse is 32 and angle is 45

Physics
1 answer:
Lerok [7]3 years ago
8 0

Answer:

The correct option is;

c. 22.6

Explanation:

The given parameters are;

The hypotenuse of the vector = 32

The angle of the vector = 45°

Therefore, the vector component in the y-axis is given as follows;

v_y = v \times sin(\theta)

Substituting the values from the question gives;

v_y = 32 \times sin(45^{\circ}) \approx 22.6

The vector component in the y-axis, v_y, is approximately 22.6.

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A wheel of diameter 40.0 cm starts from rest and rotates with a constant angular acceleration of 3.00 rad/s^2. At the instant th
xxMikexx [17]

Answer:

ac= 15.07 m/s²

Explanation:

The Wheel rotates with a constant angular acceleration.:

Centripetal acceleration is calculated as follows:

ac =ω² *R   Formula (1)

ac =v² / R    Formula (2)

Kinematics of the wheel

We apply the equations of circular motion uniformly accelerated :

ωf²= ω₀² + 2αθ  Formula (3)

v = ω* R Formula (4)

Where:

θ : angle that the wheel has rotated in a given time interval (rad)

α : angular acceleration (rad/s²)

ω₀ : initial angular speed ( rad/s)

ωf : final angular speed   ( rad/s)

v: tangential velocity of a point on the rim ( m/s)

R : radius of  wheel (m)

ac: centripetal acceleration, (m/s²)

Data:

D = 40.0 cm : diameter of the wheel

R = D/2= 40.0 cm/ 2 = 20 cm = 0.2m

α = 3.00 rad/s^2

ω₀ = 0

n = 2 revolutions : number of revolutions

θ =2πn (rad) = 2π*2 (rad) = 4π rad

Calculate of the ωf

We replace data in the formula (3)

ωf²= ω₀² + 2αθ

ωf²= 0 + 2(3)(4π)

ωf²= 24π

w_{f} = \sqrt{24\pi }

ωf = 8.68 rad/s

Calculate of the v

We replace data in the formula (4)

v = ω*R

v = (8.68)*(0.2)

v = 1.736 m/s

Calculate of the ac

We replace data in the formula (1)

ac = ( ω)²*(R)

ac = (8.68)²*(0.2)

ac = 15.07  m/s²

We replace data in the formula (2)

ac = v²/ R

ac = ( 1.736  )²/(0.2)

ac = 15.07  m/s²

7 0
4 years ago
You throw a ball upward from a window at a speed of 2.0 m/s. the ball accelerates at 9.8 m/s2. how fast is it moving when it hit
Nastasia [14]
At the point where the ball stops it has speed of 0 m/s. When it continues to fall in every meter it gets 9.8 m/s so you just put this :
9.8 m/s2 x 2.5 m = 24.5 m/s
6 0
4 years ago
2. Using the same list of living things show how they could be classified into three groups.
kati45 [8]
You can do animals that have 4 legs (dogs, horses), animals that fly (parrot, eagle), animals that live in the water (goldfish,bass)
3 0
3 years ago
Read 2 more answers
A handel or knob is fixed at the free end of door. Why?
andriy [413]
Maximum torque.
T=F.r
r is measured from point of turning, which is the hinge. r is maximum when the handle is at the free edge.
5 0
3 years ago
4. Which of the following would be a good reference point to describe the motion of a dog?
saul85 [17]

ANOTHER RUNNING DOG

Explanation:

In the given question it is to find a suitable reference point to describe  the motion of dog. Here I could suggest that it is better to compare the dog with  another running dog to create the relative speed difference to get a reliable motion variation.

Because the motion of dog is in the linear with respect to the another dog and to the acceleration produced by the dog in the required interval is easy to calculate with respect to  another dog which is already in motion.

Hence, I suggest that Motion of dog can be analysed better by analyse the motion variation of dog with  another dog running.

4 0
3 years ago
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