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ivanzaharov [21]
3 years ago
15

An old clock has a spring that must be wound to make the clock hands move. Which statement describes the energy of the spring an

d hands of the clock?
A) The spring has kinetic energy and the hands have kinetic energy.


B) The spring has kinetic energy and the hands have potential energy.


C) The spring has potential energy and the hands have potential energy.
Eliminate

D) The spring has potential energy and the hands have kinetic energy.
Physics
2 answers:
Allushta [10]3 years ago
6 0

Answer:

D) The spring has potential energy and the hands have kinetic energy.

Explanation:

Since the hands are in motion and the spring is wound, the spring has potential energy and the hands have kinetic energy.

kondaur [170]3 years ago
4 0
<span>D) The spring has potential energy and the hands have kinetic energy. </span>
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Suppose that on a hot (33.0°C) and sticky (80% humidity) afternoon in the spring, a tornado passes over the high school. If the
pickupchik [31]

Answer:

   V₂  =  225 m^{3}

so no exact option is match with the calculated answer.

Explanation:

According to Boyle's Law, we have

                                     P_1 V_1  =  P_2 V_2    ----------- (1)

Data Given;

                  P_1  =  1.0 atm

                  V_1  =  180 m³

                  P_2  =  0.80 atm

                  V_2  =  ?

Solving equation 1 for V₂,

                  V_2= \frac{P_1 V_1}{P_1}

Putting values,

                   V_2 = \frac{1.0*180}{0.80}

                  V_2 = 225 m^{3}

so no exact option is match with the calculated answer.

                 

6 0
4 years ago
Read 2 more answers
Because of surface tension, it is possible, with care, to support an object heavier than water on the water surface. The maximum
boyakko [2]

Answer:

\pi 1 = \frac{h}{l}

\pi 2 = б / l^2gp

\frac{h}{l} = Ф ( б / l^2gp )

Explanation:

<u>Develop a suitable set of dimensionless parameters for this problem</u>

The set of dimensionless parameters for this problem is :

\pi 1 = \frac{h}{l}

\pi 2 = б / l^2gp

\frac{h}{l} = Ф ( б / l^2gp )

and they are using the pi theorem, MLT systems

attached below is a detailed solution

7 0
3 years ago
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fredd [130]

Answer:

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Explanation:

The biosphere consist of all living organisms

6 0
3 years ago
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A 1100 kg car rounds a curve of radius 68 m banked at an angle of 16 degrees. If the car is traveling at 95 km/h, will a frictio
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Answer:

Yes. Towards the center. 8210 N.

Explanation:

Let's first investigate the free-body diagram of the car. The weight of the car has two components: x-direction: towards the center of the curve and y-direction: towards the ground. Note that the ground is not perpendicular to the surface of the Earth is inclined 16 degrees.

In order to find whether the car slides off the road, we should use Newton's Second Law in the direction of x: F = ma.

The net force is equal to F = \frac{mv^2}{R} = \frac{1100\times (26.3)^2}{68} = 1.1\times 10^4~N

Note that 95 km/h is equal to 26.3 m/s.

This is the centripetal force and equal to the x-component of the applied force.

F = mg\sin(16) = 1100(9.8)\sin(16) = 2.97\times10^3

As can be seen from above, the two forces are not equal to each other. This means that a friction force is needed towards the center of the curve.

The amount of the friction force should be 8.21\times 10^3~N

Qualitatively, on a banked curve, a car is thrown off the road if it is moving fast. However, if the road has enough friction, then the car stays on the road and move safely. Since the car intends to slide off the road, then the static friction between the tires and the road must be towards the center in order to keep the car in the road.

5 0
3 years ago
In any system, the _____ in the system remains constant, while the PE or KE may change.
vladimir1956 [14]

Answer:

The sum of PE and KE remains constant

Explanation:

6 0
3 years ago
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