Question

The sum of 5 consecutive integers is 505. what is the third number in this sequence?

Answer 1

Answer
 101

Explanation
Let the first term of the sequence to be a. 

1st term = a
2nd term = a+1
3rd term = a+2 
4th term = a+3
5th term =a+4

a+(a+1)+(a+2)+(a+3)+(a+4)=505
5a+10=505
5a=505-10
5a=495
a=99

3rd term = a+2
                =99+2
                = 101

Answer 2

The 5 consecutive numbers are 99,100,101,102 and 103.
Therefore 101 is the third consecutive number.