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goldfiish [28.3K]
3 years ago
7

The sum of 5 consecutive integers is 505. what is the third number in this sequence?

Mathematics
2 answers:
pantera1 [17]3 years ago
8 0
<u>Answer</u>
 101

<u>Explanation</u>
Let the first term of the sequence to be a. 

1st term = a
2nd term = a+1
3rd term = a+2 
4th term = a+3
5th term =a+4

a+(a+1)+(a+2)+(a+3)+(a+4)=505
5a+10=505
5a=505-10
5a=495
a=99

3rd term = a+2
                =99+2
                = 101

frosja888 [35]3 years ago
6 0
The 5 consecutive numbers are 99,100,101,102 and 103.
Therefore 101 is the third consecutive number.
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Read 2 more answers
Use vieta's theorem to solve the problems.
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Using Vieta's Theorem, it is found that c = 72.

<h3>What is the Vieta Theorem?</h3>
  • Suppose we have a quadratic equation, in the following format:

y = ax^2 + bx + c

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The Theorem states that:

p + q = -\frac{b}{a}

pq = \frac{c}{a}

In this problem, the polynomial is:

x^2 - 17x + c

Hence the coefficients are a = 1, b = -17.

Since the difference of the solutions is 1, we have that:

p - q = 1

p = 1 + q

Then, from the first equation of the Theorem:

p + q = -\frac{b}{a}

1 + q + q = 17

2q = 16

q = 8

p = 1 + q = 9

Now, from the second equation:

pq = \frac{c}{a}

72 = c

c = 72

To learn more about Vieta's Theorem, you can take a look at brainly.com/question/23509978

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