The sum of 5 consecutive integers is 505. what is the third number in this sequence?
2 answers:
<u>Answer</u>
101
<u>Explanation</u>
Let the first term of the sequence to be a.
1st term = a
2nd term = a+1
3rd term = a+2
4th term = a+3
5th term =a+4
a+(a+1)+(a+2)+(a+3)+(a+4)=505
5a+10=505
5a=505-10
5a=495
a=99
3rd term = a+2
=99+2
= 101
The 5 consecutive numbers are 99,100,101,102 and 103.
Therefore 101 is the third consecutive number.
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