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gogolik [260]
3 years ago
15

Write the equation of circle with diameter of 10 units centered at (- 2, 1) .

Mathematics
1 answer:
kvasek [131]3 years ago
7 0

Answer:

(x+2)^2 + (y-1)^2 = 25

Step-by-step explanation:

We want to write the equation of a circle with a diameter of 10 units centered on (-2, 1).

Recall that the equation of a circle has the standard form:

(x-h)^2 + (y-k)^2 = r^2

Where (<em>h, k</em>) is the center and <em>r</em> is the radius.

Since our diameter is 10, our radius is 5.

And since the center is at (-2, 1), <em>h</em> = -2 and <em>k</em> = 1.

Substitute:

\displaystyle (x - (-2))^2 + (y - (1))^2 = (5)^2

And simplify. Hence, our equation is:

(x+2)^2 + (y-1)^2 = 25

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sammy [17]

Answer:

\sqrt{40} or 6.32

Step-by-step explanation:

We can find the distance between two points by using this formula

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

where the x and y values are derived from the given points

The points given are ( -2 , 5 ) and ( 4 , 3 )

So we plug in the x and y values of those coordinates into the distance formula

\sqrt{(4-(-2)^2+(3-5)^2} \\4-(-2)=6\\3-5=-2\\d=\sqrt{6^2+-2^2} \\6^2=36\\-2^2=4\\36+4=40\\d=\sqrt{40}

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