All categories

3 years ago

How to determine open interval on which the function is increasing?

Mathematics

1 answer:

emmasim [6.3K]3 years ago

7 0

Answer:

To find when a function is increasing, you must first take the derivative, then set it equal to 0, and then find between which zero values the function is positive. Now test values on all sides of these to find when the function is positive, and therefore increasing.

You might be interested in

If x = 8 units, y = 3 units, and h = 10 units, find the area of the trapezoid shown above using decomposition.

kondaur [170]

If by decomposition you mean breaking it ino parts then

break it itno 2 triangles and 1 rectangle

left to right

triangle with base y and height h
h=10
y=3
area of traignel=1/2bh
aera=1/2(10)(3)
area=5(3)
area=15

rectangel of legnth x and height h
area=legnth timwe width
x=8
h=10
area=8 times 10
aera=80

last triangle
should be same as other sinces same base (y) and same height (h)
15

add
15+80+15=120

8 0

3 years ago

Read 2 more answers

PLEASE HELP ON TIMER!!!!!

Lesechka [4]

Answer:

Step-by-step explanation:

6 0

3 years ago

Connor wants to save up money to buy his math teacher a PS5 for the holidays. After 4 weeks, he has $178 saved up. After 9 weeks

Scorpion4ik [409]

Answer:

1.) Over these two moments he has saved up more money to buy a PS5 for his teacher

2.) $32 dollars per week

3.) $178

Step-by-step explanation:

2.) 338-178= 160/5= $32

3.)$178

7 0

3 years ago

Read 2 more answers

Writing expressions word prob

insens350 [35]

Don’t follow the link he or she gave you.

7 0

3 years ago

With a little care, you can find the median and the quartiles from the histogram. what are these numbers? you can also find the

coldgirl [10]

Complete Question

The histogram from this question is shown on the first uploaded image

Answer:

The first quartile is $1st Q = 19^{th} girl (subject ) = 1 \serving\ of\ fruit\ per\ day$

The median is $Median = 38 ^{th} \ girl (subject) = 2 \serving\ of\ fruit\ per\ day$

The third quartile is $3rd Q = 56^{th} \ girl (subject) = 4 \serving\ of\ fruit\ per\ day$

The mean is $\= x = 2.62$

Step-by-step explanation:

From the question we are told that

The total number of girls is n = 74

Generally the median is mathematically represented as

$Median = \frac{\frac{n}{2} +[ \frac{n}{2} + 1] }{2}$

$Median = \frac{\frac{74}{2} +[ \frac{74}{2} + 1] }{2}$

=> $Median = \frac{37 +38 }{2}$

=> $Median =37.5 \ girl$

From the histogram $37.5 \approx 38^{th} \ girl$ fall under 2 fruits per day

Generally the first quartile is mathematically represented as

$1st \ Q = \frac{\frac{n}{4} + [\frac{n}{4} + 1] }{2}$

=> $1st \ Q = \frac{\frac{74}{4} + [\frac{74}{4} + 1] }{2}$

=> $1st \ Q = 19 \ girl$

From the histogram $19^{th}$ girl fall under 1 fruit per day

Generally the third quartile is mathematically represented as

$3rd\ Q = \frac{\frac{n}{2} + n }{2}$

=> $3rd\ Q = \frac{\frac{74}{2} + 74 }{2}$

=> $3rd\ Q = 55.5$

From the histogram $55.5 \approx 56^{th} \ girl$ fall under 4 fruits per day

Generally from the histogram table the frequency [number of subjects (girls) ] and the servings of fruit per day can be represented as

Total

x(servings per day ) 0 1 2 3 4 5 6 7 8

f (number of subjects ) 15 11 15 11 8 5 3 3 3 $\sum f = 74$

xf 0 11 30 33 32 25 18 21 24 $\sum xf = 194$

Generally the mean is mathematically represented as

$\= x = \frac{1}{ \sum f} * [\sum xf]$

=> $\= x = \frac{1}{ 74} *194$

=> $\= x = 2.62$

4 0

3 years ago