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harkovskaia [24]
2 years ago
15

A CD with a diameter of 120 millimeters rotates a rate of 45 revolutions per minute. Find the linear speed of the CD in millimet

ers per minute. And find the angular speed of the CD in radians per minute
Mathematics
1 answer:
ale4655 [162]2 years ago
6 0

9514 1404 393

Answer:

  • 16,965 mm/min
  • 90π ≈ 282.7 radians/min

Step-by-step explanation:

The circumference of the CD is ...

  C = πd

  C = π(120 mm) ≈ 376.99 mm

This is the distance a point on the edge of the CD will travel when making one revolution. It will travel 45 times this far when making 45 revolutions:

  (376.99 mm/rev)(45 rev/min) ≈ 16,965 mm/min

__

There are 2π radians in each revolution, so the angular speed is ...

  (2π rad/rev)(45 rev/min) = 90π rad/min ≈ 282.7 rad/min

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medium triangle 11/x
5.7/11=11/x
x=11*11/5.7≈21.2 (longer leg of the medium triangle)
difference between 6 and 5.7 is 6-5.7=0.3 ,

screen going to be 0.3 feet less, than leg of the medium triangle that was found
21.2-0.3=20.9 ft

5 0
3 years ago
What is the degree of the polynomial?<br> 5x^3<br><br> 0<br> 1<br> 2<br> 3
Trava [24]
I guess it is d: three

4 0
3 years ago
Read 2 more answers
we believe that 42% of freshmen do not visit their counselors regularly. For this year, you would like to obtain a new sample to
Maksim231197 [3]

Answer:

A sample of 1077 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

42% of freshmen do not visit their counselors regularly.

This means that \pi = 0.42

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.

How large of a sample size is required?

A sample size of n is required, and n is found when M = 0.035. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.035 = 2.327\sqrt{\frac{0.42*0.58}{n}}

0.035\sqrt{n} = 2.327\sqrt{0.42*0.58}

\sqrt{n} = \frac{2.327\sqrt{0.42*0.58}}{0.035}

(\sqrt{n})^2 = (\frac{2.327\sqrt{0.42*0.58}}{0.035})^2

n = 1076.8

Rounding up:

A sample of 1077 is required.

3 0
3 years ago
PLEASE HELP ME ASAP!!​
marshall27 [118]

Answer:

(0.5, 0.5)

Step-by-step explanation:

Use the midpoint formula: (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

The points are:

  • A(-2, 4)
  • C(3, -3)

(\frac{-2+3}{2},\frac{4-3}{2})\\\\(\frac{1}{2},\frac{1}{2})

Therefore, the midpoint between A and C is located at (0.5, 0.5).

6 0
2 years ago
30.00
GalinKa [24]

Answer:

  (13,-23)

Step-by-step explanation:

Comparing the image coordinates to the transformation rule, you see that ...

  (x -4, y +15) = (9, -8)

Adding (4, -15) to these coordinates, we get ...

  (x -4, y +15) +(4, -15) = (9, -8) +(4, -15)

  (x-4+4, y+15-15) = (9+4, -8-15)

  (x, y) = (13, -23) . . . . coordinates of D

4 0
3 years ago
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