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harkovskaia [24]
3 years ago
15

A CD with a diameter of 120 millimeters rotates a rate of 45 revolutions per minute. Find the linear speed of the CD in millimet

ers per minute. And find the angular speed of the CD in radians per minute
Mathematics
1 answer:
ale4655 [162]3 years ago
6 0

9514 1404 393

Answer:

  • 16,965 mm/min
  • 90π ≈ 282.7 radians/min

Step-by-step explanation:

The circumference of the CD is ...

  C = πd

  C = π(120 mm) ≈ 376.99 mm

This is the distance a point on the edge of the CD will travel when making one revolution. It will travel 45 times this far when making 45 revolutions:

  (376.99 mm/rev)(45 rev/min) ≈ 16,965 mm/min

__

There are 2π radians in each revolution, so the angular speed is ...

  (2π rad/rev)(45 rev/min) = 90π rad/min ≈ 282.7 rad/min

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List two numbers that are divisible by 9?
atroni [7]

Answer:

3, 6, 12, 15

Step-by-step explanation:

3/12= 4

3/9= 3

7 0
3 years ago
Explain how to use the distributive property to find the product 3 x 4 1/5
NikAS [45]

Answer:

12.6

Step-by-step explanation:

The answer is 12.6 and here is the explanation of using the Distributive Property. Because we are multiplying a whole number by a mixed number, we have to multiply the whole number by the whole number in the mixed number and then multiply the whole number by the fraction. In this case, we have 3 x 4 1/5. We multiply 3x4=12 first, and then we multiply 3x1/5 to get 0.6. 12+0.6=12.6. Hope it helps!

5 0
3 years ago
Factor completely:<br>64 - y^3
madam [21]
From your equation, you can see that you have a difference of two cubes (aka two cubes being subtracted): 64, which is 4^{3}, and y^{3}.

There is rule for the difference of two cubes:
The difference of two cubes is equal to the difference of the cube roots times a binomial, which is the sum of the squares of the roots plus the product of the roots.

That sounds pretty confusing, but it's much easier to understand when put mathematically. Let's say our two cubes are a^{3} and b^{3}. The difference of those two cubes is:
a^{3} - b^{3} = (a - b)( a^{2} + ab + b^{2})

In our problem, a = 4 (since a^{3} = 64) and b = y (since b^{3} = y^{3}. Plug these values into the rule to find the factor of 64 - y^3:
64 - y^3 \\&#10;= (4 - y)( 4^{2} + 4y + y^{2}) \\&#10;=  (4 - y)( 16 + 4y + y^{2})

-----

Answer: (4 - y)( 16 + 4y + y^{2})

8 0
3 years ago
imagine reporting a question like if you dont like it just go to anothr question like yall be pressed for what.... love yall tho
mario62 [17]

Answer:

what the heck

was that also i'm country

Step-by-step explanation:

4 0
3 years ago
Complete the statements.
spayn [35]

Answer:

1. 30

2. 150

Step-by-step explanation:

3tan^2(x)-1 =0

Lets assume tan(x) = u

3u^2(x)-1 =0

Now we solve for 'u'

add 1 on both sides

3u^2(x) =1, divide both sides by 3

u^2 = \frac{1}{3}

Take square root on both sides

u = +-\frac{1}{\sqrt{3} }

We replace tan(x) for 'u'

tan(x) = +-\frac{1}{\sqrt{3} }  

x = 30 because tan(30) =+\frac{1}{\sqrt{3} }  in first quadrant

      x = 30      (tan is positive in first quadrant)

tan(x) =-\frac{1}{\sqrt{3} }                                                    

  x = 150 because tan(150) =-\frac{1}{\sqrt{3} }  in second quadrant

     tan is negative in second quadrant




4 0
3 years ago
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