Explain why you can not use a physical reaction to separate elements that are chemically bonded together

Chemistry

1 answer:

Rainbow [258]3 years ago

3 0

Their atoms are too tightly bonded to each other for them to be separated by a physical reaction

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How do you count atoms in a chemical formula?

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To find out the number of atoms: MULTIPLY all the SUBSCRIPTS in the molecule by the COEFFICIENT

Explanation:

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The mole concept will most likely be used in

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determining how many ozone molecules are lost in the atmosphere

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Most sulfide compounds of the transition metals are insoluble in water. Many of these metal sulfides have striking and character

docker41 [41]

Answer:

$Fe^{2+}(aq)+H_2S(aq)\rightarrow FeS (s)+2H^+ (aq)$

$2Cr^{3+}(aq)+3H_2S(aq)\rightarrow Cr_2S_3 (s)+6H^+ (aq)$

$Ni^{2+}(aq)+H_2S(aq)\rightarrow NiS (s)+2H^+ (aq)$

Explanation:

We're given the following ions:

$Fe^{2+}, Cr^{3+}, Ni^{2+}$

Hydrogen sulfide is a weak acid, so it only ionizes to ions to a very low extent. This means we would expect to see it in a molecular form in a net ionic equation rather than a dissociated form (hydrogen cations and sulfide anions). In each of these net ionic equations, we expect the three cations to displace hydrogen from hydrogen sulfide and form three precipitates.

Firstly, iron(II) displaces hydrogen forming iron(II) sulfide and acidic conditions:

$Fe^{2+}(aq)+H_2S(aq)\rightarrow FeS (s)+2H^+ (aq)$

Secondly, chromium(III) cation displaces hydrogen forming chromium(III) sulfide:

$2Cr^{3+}(aq)+3H_2S(aq)\rightarrow Cr_2S_3 (s)+6H^+ (aq)$

Thirdly, nickel(II) cation displaces hydrogen forming nickel sulfide:

$Ni^{2+}(aq)+H_2S(aq)\rightarrow NiS (s)+2H^+ (aq)$

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Answer: $6.12\times 10^{14}$ Hz

Explanation: Recall the formula for the speed of light is

$c=\lambda v$

where $c$ is the speed of light, $\lambda$ is the wavelength, and $v$ is the frequency. Assuming this takes place in a vacuum, $c=3.00\times 10^8$ m/s. Now we can solve for frequency