The correct answer is D: Watt. This unit was named after James Watt, and
is used to express the equivalent of one joule per second in energy. In
experiments and on the packaging for electrical products such as light-bulbs, the measurement will usually be written in its abbreviated
format: W.
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This question involves the concepts of orbital velocity and orbital radius.
The orbital velocity of ISS must be "7660.25 m/s".
The orbital velocity of the ISS can be given by the following formula:

where,
v = orbital velocity = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
M = Mass of Earth = 5.97 x 10²⁴ kg
R = orbital radius = radius of earth + altitude = 63.78 x 10⁵ m + 4.08 x 10⁵ m
R = 67.86 x 10⁵ m
Therefore,

<u>v = 7660.25 m/s</u>
Learn more about orbital velocity here:
brainly.com/question/541239
<u>We are given:</u>
Mass of the Steelhead(m) = 9 kg
Velocity of the Steelhead(v) = 16 m/s
<u>Calculating the Kinetic Energy:</u>
KE = 1/2mv²
replacing the variables
KE = 1/2 * 9 * (16)²
KE = 1152 Joules
Answer:
f = 4000 / 30 sec = 133.3 vibrations/sec
P = 1 / f = .0075 sec period of 1 vibration