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Lostsunrise [7]
3 years ago
14

On Apollo Moon missions, the lunar module would blast off from the Moon's surface and dock with the command module in lunar orbi

t. After docking, the lunar module would be jettisoned and allowed to crash back onto the lunar surface. Seismometers placed on the Moon's surface by the astronauts would then pick up the resulting seismic waves.
Find the impact speed of the lunar module, given that it is jettisoned from an orbit 110 km above the lunar surface moving with a speed of 1600 m/s .
My Approach:
Ei = Ef
1/2*m*vi2 - (G*m*ME)/(radius of moon + orbital distance) = 1/2*m*vf2 ​- (G*m*ME)/r
=> (0.5 * m * 16002) - (6.67 * 10-11 * 7.35*1022 * m/(1737.4*103 +180*103) = (0.5*m*v^2) - (6.67*10-11 * 7.35*1022 * m/(1737.4*103 )
Physics
1 answer:
LiRa [457]3 years ago
5 0

Answer:

Following are the solution to the given question:

Explanation:

For crashing speed, we can use energy conservation:

kinetic energy = \frac{1}{2}\times m \times v^2  

potential energy = -\frac{GMm}{r}

moon mass= 7.36\times 10^{22} \ kg

Radius= 1738\  km  

\to (K + U) \ orbit = (K + U)\ crash\\\\\to \frac{1}{2}\times m \times v_o^2 - \frac{GMm}{(1738000 + 110000)} \\\\ \to \frac{1}{2}\times m \times vc^2 - \frac{GMm}{1738000}

Calculating the mass drop for the leave:

\to \frac{vo^2}{2} - \frac{GM}{1848000}\\\\ \to \frac{vc^2}{2} - \frac{GM}{1738000}

Solve the value for

vc = \sqrt{(vo^2 +2\times GM \times(\frac{1}{1738000} - \frac{1}{1848000}))}\\\\vc = \sqrt{(1600^2 +2\times 6.67\times 10^{-11} \times 7.36 \times 10^{22}\times (\frac{1}{1738000} - \frac{1}{1848000}))}\\\\vc = 1701 \ \frac{m}{s}\\\\  

The approach is correct but misrepresented in replacing 180 km instead of 110 km.

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A 2.0 kilogram ball rolling along a flat surface starts up a hill. If the ball reaches a height of 0.63 meters, what was its ini
Agata [3.3K]
The potential energy as it reaches a height of 0.63 meters is mgh
Since total mechanical energy is conserved, Set that equal to the initial kinetic energy which is 0.5mv^2

2*9.8*0.63 = 0.5*2*v^2
12.348 = v^2
3.51 = v

That's it's initial speed.
5 0
3 years ago
Select all that apply. What factors can limit growth?
Rudiy27
A, b and d

Competition for fix resources of course increases the energy expenditure needed to gather those resources and leaves less for a given population. A lower amount of sunlight or water also contributes to decreased energy which lowers growth. Finally, small borders limit growth in that population density can only go so high before the death rate increases beyond the birth rate.
8 0
3 years ago
Read 2 more answers
Two charged plates separated by 15 cm create a uniform electric field of 360 n/c. what is the potential difference between the p
nikitadnepr [17]

When two charged plates are separated by a distance, the potential difference between the plates is 54 Volts.

<h3>What is uniform electric field?</h3>

The electric field intensity which does not increase or decrease with time or remain constant is called the uniform electric field.

Given is the plates separated by distance d = 15 cm =0.15 m, electric field E= 360 N/C.

The relation between the electric field and voltage is

E=V/d

Substitute the values into the expression to get the potential difference V,

V = 360 x 0.15

V = 54 Volts

Thus, the potential difference between the plates is 54 Volts.

Learn more about uniform electric field.

brainly.com/question/26446532

#SPJ1

8 0
3 years ago
3. Which equation shows the relationship between the Kelvin and Celsius temperature scales? K = 273 – °C K = °C + 273 K = °F + 2
Alborosie

Answer: K=\°C+273.15

Explanation:

The Kelvin (K), is the unit of temperature of the scale created by the British physicist William Thomson (Lord Kelvin) in 1848, <u>taking as a base the Celsius scale</u>, establishing the zero point for this scale in the absolute zero which is in -273.15\°C.

This was achieved by observing that when a gas cools, its volume decreases proportionally to its temperature. That is, <u>for each degree of temperature that the gas decreases, its volume also decreases by a certain percentage. </u>

After which, Kelvin made the calculations and it turned out that at a temperature of -273.15\°C the volume of the gas would be zero (theoretically).

It should be noted that the Kelvin is the unit of temperature of the International System of Units and that although the scale starts at absolute zero (theoretical), in which no molecule should move, in reality it is not so, because according to quantum physics, at this temperature the molecules retain a residual movement.

7 0
4 years ago
Caroline, a piano tuner, suspects that a piano's B4 key is out of tune. Normally, she would play the key along with her B4 tunin
Sergeeva-Olga [200]

Answer:

455.9 Hz, Flat

Explanation:

The beat frequency is basically the difference between the frequency of the B4 note and the frequency of the A4 tuning fork. This means the B4 note is 15.9 Hz off of 440Hz, and 67.4 Hz off of 525.3 Hz. As B4 is between the two notes, it would make sense to find its frequency by adding 15.9 to 440 and subtracting 67.4 from 523.3, both if which give us a frequency 455.9 Hz for the B4 key. This is because the note doesn't change for the different turning forks so both differences should result in the same frequency. Because the note should be 493.9 frequency but instead has a frequency of 455.9 Hz, it is flat because the frequency is lower than it is supposed to be.

Hope this helped!

7 0
4 years ago
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