Answer is: <span>C.)It will be closer to the mass of Vi–193.
</span><span>Average atomic mass of vitellium =
Ar(Vi-188) </span>· ω(Vi-188) + Ar(Vi-191) · ω(Vi-191) + Ar(Vu-193) · ω(Vi-193).
Average atomic mass of vitellium =
187.9122 amu · 0,10861 + 190.9047 amu · 0,12428 + 192.8938 amu · 0,76711.
Average atomic mass of vitellium = 20,409 + 23,725 + 147,970.
Average atomic mass of vitellium = 192,104.
The answer to this would be 22 mL
Answer:
1. The α particles were repelled by electrons.
Explanation:
The gold foil experiment was performed by Rutherford and his research group in 1911 (at the beginning of the 20th century). In this experiment, α particles were bombed to gold foils, and films were placed surround it to collect the particles.
It was observed that most of the particles passed through of the foil undeflected, and for that, Rutherford stated that the atom was a "huge empty". Some particles were deflected, because they're attracted to the electrons at the electrosphere, and a small number of particles were complete deflected to the origin because they chocked with the small positive nuclei.
Thus, the experiment suggested the nuclear model of the atom, called the planetary model, that was improved after by Bohr and other scientists in the quantum model.
Answer:
1.Every object in a state of uniform motion tends to remain in that state of motion unless an external force is applied to it.
2.The relationship between an object's mass m, its acceleration a, and the applied force F is F = ma.
3.For every action there is an equal and opposite reaction.
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Pls Mark <em><u>Brainliest</u></em> I just need one more!
Answer:
Option C is false statement. The half life of a second order reaction is not dependent on concentration.
Explanation:
Half life of a reaction is defined as the amount of time which is required for a reactant concentration reduced by half comparison to its initial concentration.
Half life of a second order reaction is depend on the initial concentration of a reaction, in contrast to 1st order reaction.