Newton's first law of motion states that an object at rest stays at rest unless acted upon by a force while an object at motion stays in motion unless acted upon by an opposite force. Therefore, the ball in motion will stay at motion considering there is no friction force in the field, answer is A. If the field has friction force against the ball then it will slow down and stop eventually, answer is B.
<h2><u>Question</u><u>:</u><u>-</u></h2>
Ryan applied a force of 10N and moved a book 30 cm in the direction of the force. How much was the work done by Ryan?
<h2><u>Answer:</u><u>-</u></h2>
<h3>Given,</h3>
=> Force applied by Ryan = 10N
=> Distance covered by the book after applying force = 30 cm
<h3>And,</h3>
30 cm = 0.3 m (distance)
<h3>So,</h3>
=> Work done = Force × Distance
=> 10 × 0.3
=> 3 Joules
Velocidad inicial = 20 m/s
velocidad final = 0 m/s
aceleracion = -2 m/s^2
aceleracion = (cambio de velocidad)/(cambio de tiempo)
(cambio de tiempo)= (cambio de velocidad)/aceleracion
tiempo = (-20 m/s)/(-2 m/s^2)
= 10 segundos
x = (x(inicial)) + (v(inicial))(tiempo) + 1/2(aceleracion)(tiempo)^2
x(inicial) = 0
x = (20 m/s)(10 s) + 1/2 (-2m/s^2)(10 s)^2
x = 200 m - 100 m
x = 100 m (el espacio recorrido en los dos segundos)
espero que esto te ayude! buena suerte!
Data:
a) v = 84 m/s
r = 225 m
Ac =?
b) Ac = 9.8 m/s^2
v = ?
Formula: Ac = v^2 / r
Solution
a) Ac = (84 m/s)^2 / (225 m) = 31.36 m/s^2
To measure it in terms of g, divide by g = 9.8 m/s^2
=> Ac = 31.36 m/s^2 / [ 9.8 m/s^2 / g] = 3.2 g
Answer: Ac = 3.2 g
b) Ac = 9.8 m/s^2
v^2 = Ac * r = 9.8 m/s^2 * 225 m = 2,205 m^2 / s^2
=. v = 46.96 m/s ≈ 47 m/s
Answer: 47 m/s
It would be the bus moving at 25mph
Talking in terms of momentum, we know that momentum is conserved in a collision. Something that will cause the most 'damage' is something that posses more energy or momentum
p=mv
with velocity being the same, the object with the greater mass (the bus) will have a larger momentum and will thus cause more damage. <span />