Amplitude: How dense the medium is in the compression part of the wave, and how empty the rarefied area is.
Frequency: The number of wavelengths that pass a position in 1 second.
loudness: The quality of the sound that is most closely linked to the amplitude of the sound wave.
Period: The amount of time that it takes one wavelength to pass by a position.
Pitch: The quality of the sound that is most closely linked to the frequency of the sound wave.
Answer:
For number 2, it will be 8.
So the acceleration of gravity is 9.8 m/s so that’s how quickly it will accelerate downwards. You can use a kinematic equation to determine your answer. We know that initial velocity was 19 m/s, final velocity must be 0 m/s because it’s at the very top, and the acceleration is -9.8 m/s. You can then use this equation:
Vf^2=Vo^2+2ax
Plugging in values:
361=19.6x
X=18 m
Answer:
Δ L = 2.57 x 10⁻⁵ m
Explanation:
given,
cross sectional area = 1.6 m²
Mass of column = 26600 Kg
Elastic modulus, E = 5 x 10¹⁰ N/m²
height = 7.9 m
Weight of the column = 26600 x 9.8
= 260680 N
we know,
Young's modulus=![\dfrac{stress}{strain}](https://tex.z-dn.net/?f=%5Cdfrac%7Bstress%7D%7Bstrain%7D)
stress = ![\dfrac{P}{A}](https://tex.z-dn.net/?f=%5Cdfrac%7BP%7D%7BA%7D)
= ![\dfrac{260680}{1.6}](https://tex.z-dn.net/?f=%5Cdfrac%7B260680%7D%7B1.6%7D)
= 162925
strain = ![\dfrac{\Delta L}{L}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5CDelta%20L%7D%7BL%7D)
now,
![Y = \dfrac{stress}{strain}](https://tex.z-dn.net/?f=Y%20%3D%20%5Cdfrac%7Bstress%7D%7Bstrain%7D)
![\Delta L = \dfrac{162925}{Y}\times L](https://tex.z-dn.net/?f=%5CDelta%20L%20%3D%20%5Cdfrac%7B162925%7D%7BY%7D%5Ctimes%20L)
![\Delta L = \dfrac{162925}{5 \times 10^10}\times 7.9](https://tex.z-dn.net/?f=%5CDelta%20L%20%3D%20%5Cdfrac%7B162925%7D%7B5%20%5Ctimes%2010%5E10%7D%5Ctimes%207.9)
Δ L = 2.57 x 10⁻⁵ m
The column is shortened by Δ L = 2.57 x 10⁻⁵ m