Answer:
See Explanation
Explanation:
The frequency of sound waves received by the microphone influences the output or pitch of the sound obtained from the microphone.
The higher the frequency of the sound received by the microphone, the higher the output of the microphone and vice versa. This is because, the higher the frequency of sound, the higher the oscillations produced and the greater the output of the microphone.
The rise and fall in the pitch of sound waves as the frequency of sound waves varies is called inflection.
<h2>
Answer:g=9.79
,A object of mass
![m](https://tex.z-dn.net/?f=m)
at the surface of earth experiences a force
![mg](https://tex.z-dn.net/?f=mg)
</h2>
Explanation:
Let
be the mass of earth.
Let
be the radius of earth.
Let
be the universal gravitational constant.
Given,
![M=5.96\times 10^{24}Kg](https://tex.z-dn.net/?f=M%3D5.96%5Ctimes%2010%5E%7B24%7DKg)
![R=6.37\times 10^{6}m](https://tex.z-dn.net/?f=R%3D6.37%5Ctimes%2010%5E%7B6%7Dm)
![G=6.67259 \times 10^{-11}](https://tex.z-dn.net/?f=G%3D6.67259%20%5Ctimes%2010%5E%7B-11%7D)
![Nm^{2}Kg^{-2}](https://tex.z-dn.net/?f=Nm%5E%7B2%7DKg%5E%7B-2%7D)
Let
be the acceleration due to gravity.
Then,![g=\dfrac{GM}{R^{2}}](https://tex.z-dn.net/?f=g%3D%5Cdfrac%7BGM%7D%7BR%5E%7B2%7D%7D)
![g=\frac{6.67259 \times 10^{-11}\times 5.96\times 10^{24}}{(6.37\times 10^{6})^{2}}](https://tex.z-dn.net/?f=g%3D%5Cfrac%7B6.67259%20%5Ctimes%2010%5E%7B-11%7D%5Ctimes%205.96%5Ctimes%2010%5E%7B24%7D%7D%7B%286.37%5Ctimes%2010%5E%7B6%7D%29%5E%7B2%7D%7D)
![g=9.79ms^{-2}](https://tex.z-dn.net/?f=g%3D9.79ms%5E%7B-2%7D)
A object of mass
at the surface of earth experiences a force ![mg](https://tex.z-dn.net/?f=mg)
Answer:
11.27N
Explanation:
Given parameters:
Mass of the book = 1.15kg
Unknown:
Magnitude of the normal force = ?
Solution:
The normal force is the vertical force exerted by a body on an object.
It can be described as the weight of an object.
Normal force = mass x acceleration due to gravity
Normal force = 1.15 x 9.8 = 11.27N
Answer:
If the frequency of the motion of a simple harmonic oscillator is doubled , then maximum speed of the oscillator changes by the factor 2
Explanation:
We know that in a simple harmonic oscillator the maximum speed is given by
= ![Aw](https://tex.z-dn.net/?f=Aw)
Here A is amplitude which is constant , so from above equation we see that maximum speed is directly proportional to
of the oscillation .
Since ![w = 2 \pi f](https://tex.z-dn.net/?f=w%20%3D%202%20%5Cpi%20f)
= 2
Where
is the maximum speed when frequency is doubled .
Answer:
The correct answer is "64 J".
Explanation:
The given values are:
Mass,
m = 52 kg
Velocity,
v = 6 m/s
Mechanical energy,
= 1000 J
Now,
The gravitational potential energy will be:
⇒ ![P.E=1000-\frac{1}{2}mv^2](https://tex.z-dn.net/?f=P.E%3D1000-%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
![=1000-\frac{1}{2}\times 52\times (6)^2](https://tex.z-dn.net/?f=%3D1000-%5Cfrac%7B1%7D%7B2%7D%5Ctimes%2052%5Ctimes%20%286%29%5E2)
![=1000-26\times 36](https://tex.z-dn.net/?f=%3D1000-26%5Ctimes%2036)
![=1000-936](https://tex.z-dn.net/?f=%3D1000-936)
![=64 \ J](https://tex.z-dn.net/?f=%3D64%20%5C%20J)