Answer:
Explanation:
5. not necessarily so that the first object could have left with initial velocity and the second not, so even if the second has a greater acceleration its velocity is less than that of the first
6. The acceleration of the motorcycle is
SI System Reductions
Vo = 80 km / h (1000m / 1km) (1h / 3600s) = 22.2 m / s
Vf = 90 km / h (1000m / 1km) (1h / 3600s) = 25 m / s
Vf = Vo + at at = Vf-Vo
am = (Vf-Vo) / t
am = (25 -22.2) / t = 2.8 / t
am= 2.8/t
For the bike we have
Vf = 10 km / h (1000m / 1km) (1h / 3600s) = 2.78 m / s
Vo = 0
ab = (Vf -Vo) / t
ab = (2.78 -0) / t
ab = 2.8/t
Since time is the same for both of us, if we round to Significant figures the two accelerations are equal
7. If when an object is slowing or slowing down.
For example, a car goes north and must stop at the traffic light, the acceleration of the brakes goes south
8. Yes, since an object can go to the left and the acceleration to the right, but the object will lose speed over time
9. in the launch of projectiles the acceleration is negative and the speed after half the path is also negative
10. Car B must be moving to car A, because if they leave together B has more acceleration, bone that travels the distance at the same time
11. When we have friction, the velocity of an object increases by an external force, but the friction also increases the acceleration, but since it is positive, the velocity increases until the acceleration is zero and hence the velocity remains constant.
and 
, which is given by
is the Coulomb's constant.