A car initially traveling at 32.4 m/s undergoes a constant negative acceleration of magnitude 1.70 m/s2 after its brakes are app

Question

4 years ago

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A car initially traveling at 32.4 m/s undergoes a constant negative acceleration of magnitude 1.70 m/s2 after its brakes are app

lied. (a) How many revolutions does each tire make before the car comes to a stop, assuming the car does not skid and the tires have radii of 0.330 m?

Physics

1 answer:

8090 [49] · Answer 1 · 2022-01-29T18:35:33+03:00

<h2>The car tire makes 149 revolutions before coming to stop.</h2>

Explanation:

a) We have equation of motion v² = u² + 2as

Initial velocity, u = 32.4 m/s

Acceleration, a = -1.70 m/s²

Final velocity, v = 0 m/s

Substituting

v² = u² + 2as

0² = 32.4² + 2 x -1.70 x s

s = 308.75 m

Distance traveled before stopping is 308.75 m

Radius of tire = 0.330 m

Circumference of tire = 2πx 0.33 = 2.07 m

1 revolution = 2.07 m

$\texttt{Number of revolutions = }\frac{308.75}{2.07}=148.91$

The car tire makes 149 revolutions before coming to stop.