Explanation:
a) We have equation of motion v² = u² + 2as
Initial velocity, u = 32.4 m/s
Acceleration, a = -1.70 m/s²
Final velocity, v = 0 m/s
Substituting
v² = u² + 2as
0² = 32.4² + 2 x -1.70 x s
s = 308.75 m
Distance traveled before stopping is 308.75 m
Radius of tire = 0.330 m
Circumference of tire = 2πx 0.33 = 2.07 m
1 revolution = 2.07 m
The car tire makes 149 revolutions before coming to stop.
Explanation:
1. Force applied on an object is given by :
F = W = mg
(a) A 160 lb human being, F = 160 lb
g = acceleration due to gravity, g = 32 ft/s²
m = 5 kg
(b) A 1.9 lb cockatoo, F = 1.9 lb
m = 0.059 kg
2. (a) A 2300 kg rhinoceros, m = 2300 kg
(b) A 22 g song sparrow, m = 22 g = 0.022 kg
Hence, this is the required solution.
Two forces 3N and 4N act on a body in a direction due north From East, the equilibrant's angle is given by .
The equilibrium force is the balanced force when the net force acting is zero and is the exact opposite of the consequent force. The resultant force is one single force replaced by numerous forces.
<h3>Briefing:</h3>3N and 4N are the two forces pulling on a body.
The forces work along the North and the East, which are perpendicular to one another.
The resultant of the forces, which is provided by the equilibrant force,
R = √(3)²+(4)²
R = 5N
From East, the equilibrant's angle is given by
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