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polet [3.4K]
3 years ago
7

Convert 355 km/s into m/ns.

Chemistry
2 answers:
xxTIMURxx [149]3 years ago
6 0

Answer:

0.000355 meters/nanosecond (m/ns)

OLEGan [10]3 years ago
6 0

Answer:

3.55e-7

Explanation:

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To classify a substance as an Arrhenius acid or base, or as a Brønsted-Lowry acid or base, you must consider how the substance b
aleksandr82 [10.1K]

Answer:

Ammonia is an Arrhenius base and a Brønsted-Lowry base.

Explanation:

An Arrhenius base is any substance which, when it is dissolved in an aqueous solution, produces hydroxide (OH^-), ions in solution. An aqueous solution is a solution that has water present in it.

A Bronsted-Lowry base is a substance that accepts a proton, that is, a hydrogen ion (H^+).

Looking at the equation above, ammonia satisfies both characteristics. We can see that when ammonia is dissolved in water, hydroxide ions is produced in the solution. Hence it is an Arrhenius base. Similarly, the hydroxide ion is formed when ammonia accepts a proton. This is a characteristic of a Brownstead-Lowry base. Hence ammonia is both an Arrhenius base and a Brownstead-Lowry base.

4 0
4 years ago
Suppose that coal of density 1.5 g/cm^3 is pure carbon. (It is, in fact, much more complicated, but this is a reasonable first a
NISA [10]

Answer:

q = -6464.9 kJ

Explanation:

We are given that the heat of combustion is  ∆H° = −394 kJ per mol of carbon.Therefore what we need to do is calculate how many moles of C are in the lump of coal by finding its mass since the density is given.

vol = 5.6 cm x 5.1 cm x 4.6 cm = 131.38 cm³

m = d x v = 1.5 g/cm³ x 131.38 cm³ = 197.06 g

mol C = m/MW = 197.06 g/ 12.01g/mol = 16.41 mol

q =  −394 kJ /mol C x 16.41 mol C = -6464.9 kJ

7 0
3 years ago
What factor would affect the pH of a waterway?
just olya [345]
Acid Rain. Hope i helped you!
8 0
4 years ago
When was the last time that humans have left Earths orbit?
Vinvika [58]

Answer:

d

Explanation:

6 0
3 years ago
Read 2 more answers
Determine the molar solubility of AgBr in a solution containing 0.150 M NaBr. Ksp (AgBr) = 7.7 Ă— 10-13. Determine the molar sol
Kaylis [27]

Hey there!:

Given the reaction:

 NaBr  ⇌  Na⁺ +  Br⁻

  ↓              ↓         ↓

0.150M      0.150M     0.150M


AgBr ⇌ Ag⁺   + Br⁻

 ↓            ↓          ↓

 x            x         0.150M


Therefore:

Ksp = x * 0.150

x = ( 7.7 * 10⁻¹³ ) / 0.150

x = 5.1 * 10⁻¹²


Answer B


Hope that helps!

5 0
3 years ago
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