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Shtirlitz [24]
3 years ago
12

How many electrons does Br lose or gain to fill its octet?

Chemistry
1 answer:
Greeley [361]3 years ago
4 0

i think it is 8. I might be wrong.

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8 0
3 years ago
URGENT WILL GIVE BRAINLEIST In two or more complete sentences explain how to balance the chemical equation,
Pani-rosa [81]

Answer:

you add the atoms together

Explanation:

3 0
3 years ago
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What volume of 0.205 m k3po4 solution is necessary to completely react with 154 ml of 0.0110 m nicl2? 1.65 l?
sasho [114]
The balanced equation for the above reaction is 
2K₃PO₄   + 3NiCl₂  ---> 6KCl + Ni₃(PO₄)₂
stoichiometry of K₃PO₄  to NiCl₂ is 2:3
the number of NiCl₂ moles reacted - 0.0110 mol/L x 0.154 L = 1.69 x 10⁻³ mol
if 3 mol of NiCl₂ reacts with - 2 mol of K₃PO₄ 
then 1.69 x 10⁻³ mol of NiCl₂ reacts with - 2/3 x 1.69 x 10⁻³  = 1.13 x 10⁻³ mol of K₃PO₄
molarity of K₃PO₄ solution given - 0.205 M
there are 0.205 mol in 1 L
therefore 1.13 x 10⁻³ mol are in - 1.13 x 10⁻³ mol / 0.205 mol/L = 5.51 mL
volume of K₃PO₄ required - 5.51 mL
3 0
3 years ago
What is the value of work done on an object when a 50–newton force moves it 15 meters in the same direction as the force?
victus00 [196]

Answer:

work done = 750 J

Explanation:

Given data:

Force on object = 50 N

Distance covered = 15 m

Work done = ?

Solution:

W = F. d

W = work done

F = force

d = distance

Now we will put the values in formula.

W = 50 N × 15 m

W = 750 N. m = 750 J

7 0
3 years ago
Select the correct Answers.
Mandarinka [93]

Answer:

3. The temperatures of the two substances equalize.

Explanation:

  • As two objects at different temperatures are placed in contact, heat is transferred from the warmer to the cooler object until the temperature of the two objects be the same.
  • The amount of heat that is transferred from the warmer object is equal to the amount of heat that is transferred into the cooler object.
  • This is in agreement with the law of conservation of energy.
  • <em>So, the right choice is: 3. The temperatures of the two substances equalize. </em>

<em></em>

8 0
3 years ago
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