Answer:
5.625 moles of oxygen, O₂.
Explanation:
The balanced equation for the reaction is given below:
4Al + 3O₂ —> 2Al₂O₃
From the balanced equation above, 
4 moles of Al reacted with 3 moles of O₂.
Finally, we shall determine the number of mole of O₂ required to react with 7.5 moles of aluminum, Al. This can be obtained as illustrated below:
From the balanced equation above, 
4 moles of Al reacted with 3 moles of O₂.
Therefore, 7.5 moles of Al will react with = (7.5 × 3)/4 = 5.625 moles of O₂.
Thus, 5.625 moles of O₂ is needed for the reaction. 
 
        
             
        
        
        
Answer:
flourine(1681),carbon(1086),lithium(520) and potassium(419)
as we can see that the ionization energy of flourine is the highest than carbon than lithium and than potassium
Explanation:
i hope it will help you
 
        
                    
             
        
        
        
Answer:
C6H12O6
Glucose
Explanation:
Glucose is a monocarbohydrate
carbohydrates always have only C, H, and O
brainliest plz
 
        
             
        
        
        
Answer:
Like other alkali metals, rubidium metal reacts violently with water. As with potassium (which is slightly less reactive) and caesium (which is slightly more reactive), this reaction is usually vigorous enough to ignite the hydrogen gas it produces.
Explanation:
hope it helps