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3 years ago

Find the difference between the first and third angle projection type.

Engineering

1 answer:

motikmotik3 years ago

4 0

Answer:

First angle projection

1.Object is between observer and plane of projection.

2.Projection of object take on first quadrant.

3.Plane of projection is assume non transparent.

Third angle projection:

1.Plane of projection is between observer and object.

2.Projection of object take on third quadrant.

3.Plane of projection is assume transparent.

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3 years ago

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A milling operation was used to remove a portion of a solid bar of square cross section. Forces of magnitude P = 19 kN are appli

lakkis [162]

Answer:

Complete question for your reference is below.

A milling operation was used to remove a portion of a solid bar of square cross section. Forces of magnitude P = 19 kN are applied at the centers of the ends of the bar. Knowing that a = 28 mm and sigma_all = 130 MPa, determine the smallest allowable depth d of the milled portion of the bar

Explanation:

Please find attached file for complete answer solution and explanation.

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4 years ago

Find the resistance of a circuit that draws 4 amperes with 8 volts applied?

vodka [1.7K]

Answer:

2 ohms

Explanation:

V = I * R

8 = 4 * R

8 / 4 = R

R = 2 ohms

5 0

3 years ago

Because of its high dielectric strength, SF6 (sulfur hexafluoride) gas is widely used as an insulator and a dielectric in HV app

Mars2501 [29]

Answer:

5.31 × 10⁻⁴⁰ Fm²

Explanation:

Using the Clausius-Mossotti equation

(ε - 1)/(ε + 2) = Nα/3ε₀ where ε = dielectric constant = 1.0015, ε₀ = 8.854 × 10⁻¹² F/m, N = number of molecules of SF6 per unit volume and α = electronic polarizability

So, α = (ε - 1)3ε₀/[(ε + 2)N]

Also

P = (N/NA)RT where P = pressure = 1 atm = 1.013 × 10⁵ Pa, N = number of molecules of SF6 per unit volume, NA = Avogadro's constant = 6.022 × 10²³ /mol, R = molar gas constant = 8.314 J/mol-K and T = room temperature = 25° = 273 + 25 = 293 K

So, N = PNA/RT

= 1.013 × 10⁵ Pa × 6.022 × 10²³ /mol ÷ (8.314 J/mol-K × 293 K)

= 6.100286 × 10²⁸ Pa/mol ÷ (2436.002 J/mol)

= 0.0025 × 10²⁸ molecules/m³

= 2.5 × 10²⁵ molecules/m³

So,

α = (ε - 1)3ε₀/[(ε + 2)N]

α = (1.0015 - 1)× 3 × 8.854 × 10⁻¹² F/m/[(1.0015 + 2)2.5 × 10²⁵ molecules/m³]

α = (0.0015)26.562 × 10⁻¹² F/m/[(3.0015)2.5 × 10²⁵ molecules/m³]

α = 0.039843 × 10⁻¹² F/m/[7.50375 × 10²⁵ molecules/m³]

α = 0.00531 × 10⁻³⁷ Fm²

α = 5.31 × 10⁻⁴⁰ Fm²

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3 years ago

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Triss [41]

Answer: a drafting engineer

Explanation:

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