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EleoNora [17]
3 years ago
7

cThe Mars Rover Spirit got stuck in the Martian sand. The wheels kept slipping. Attempts to free it were futile. Discuss the typ

e of actuator in this case. Can you suggest any improvements in the actuator that would have prevented this unfortunate breakdown
Engineering
1 answer:
IgorC [24]3 years ago
7 0

Answer:

Improved/ advanced types of Actuators include servo systems, create a large range of actuator motion in response to the changing needs of the operational environment or process.

Actuators are local or automated suppliers of working motion.

Hydraulic and air cylinders can be classified as single-acting cylinders, meaning that the energy source result in movement in one direction and a spring is used for the other direction.

Explanation:

An actuator control system is referred to as any electronic, electrical, or electromechanical system often used to activate an actuator, control the direction as well as extent and duration of its output. Actuator control systems could take the form of extremely simple, manually-operated, start-and-stop stations, either sophisticated or programmable computer systems. The more improved/ advanced types include servo systems that produce a large range of actuator motion in response to the changing needs of the operational environment or process. This type of actuator control system uses an interface arrangement that assimilates feedback from the process or mechanism and adjusts the actuator in the right way. Most actuator systems will include at least a set of travel limits that prevent the actuator destroying itself or the secondary mechanism.

Actuators are local or automated suppliers of working motion. They are used to changes, adjust, or move a secondary mechanism, where a physical operator cannot intervene directly. They are denoted by a large range of varying types using electrical and electromagnetic, hydraulic, or pneumatic power sources to create linear or rotary outputs. One element they all have in common is the actuator control system used to start, stop, and adjust the range, speed, and duration of the working motion.

Actuators can produce a linear motion, rotary motion or oscillatory motion which means they can create motion in one direction, in a circular motion or in opposite directions at regular intervals. Hydraulic and air cylinders can be classified as single-acting cylinders, meaning that the energy source result in movement in one direction and a spring is used for the other direction.

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lisov135 [29]

Answer:

El conocer la función del sistema nervioso permite comprender la estructura del cuerpo. Puesto que, toda acción que se se realice en ella dependerá del sistema nervioso para que sea eficaz

4 0
1 year ago
For some metal alloy it is known that the kinetics of recrystallization obey the Avrami equation, and that the value of k in the
JulsSmile [24]

Answer:

t = 1456.8 sec

Explanation:

given data:

contant k = 2.60*10^{-6}

rate of crystallization is 0.0013 s-1

rate of transformation is given by

r = \frac{1}{t_0.5}

use specifies value to solve t_0.5

it is ime required for 50% tranformation

r = \frac{1}{.0013}=769.2 sec

Avrami equation is given by

y = 1 - e^{-kt^n}

0.5 = 1 - e^{-kt_0.5^n}

1-0.5 = e^{-kt_0.5^n}

ln (1 - 0.5) = -kt_0.5^n

ln \frac{ln (1 - 0.5)}{-k} = nln t_0.5

n = \frac{ ln \frac{ln (1 - 0.5)}{-k}}{ln t_0.5}

n = \frac{ ln \frac{ln (1 - 0.5)}{-2.60*10^{-6}}}{ln 769.2}

n = 1.88

second degree of recrystalization may be determine by rearranging original avrami equation

t = [\frac{-ln(1-y)}{k}]^{1/n}

for 90%completion

t = [\frac{-ln(1-0.9)}{2.60*10^{-6}}]^{1/1.88}

t = 1456.8 sec

5 0
2 years ago
How does an airfoil create lift?
scoundrel [369]

Answer:

An airfoil creates lift by exerting a downward force on the air as it flows past

3 0
2 years ago
A cylindrical bar of metal having a diameter of 20.3 mm and a length of 205 mm is deformed elastically in tension with a force o
Zarrin [17]

Answer:

a) 0.4393 mm

b)  -0.141 mm

Explanation:

Cylindrical bar :  Diameter = 20.3 mm , Length = 205 mm

Force that deforms bar of metal = 46400 N

elastic modulus = 66.9 GPa

Poisson's ratio ( u ) = 0.32

A) Determine the amount by which this specimen will elongate in the direction of applied stress

dl = \frac{P*L}{A*E}

where P = 46400 N

          L = 205 mm

          A = \frac{\pi }{4} * 20.3^2 = 323.65

          E = 66.9 GPa

dl =  ( 46400 * 205 ) / ( 323.65 * 66.9 * 10^3 )  = 0.4393 mm

B) determine the change in diameter of the specimen

change in diameter( compressed due to elongation in length )

= - u * dl

 = - 0.32 * 0.4393

=  -0.141 mm

5 0
2 years ago
Using the milligrams of ascorbic acid you entered above, the ratio of total sample volume to aliquot volume, and the total milli
Dmitriy789 [7]

Answer: 7.500 2.99

Explanation:

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2 years ago
Read 2 more answers
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