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tatiyna
2 years ago
8

For some metal alloy, the following engineering stresses produce the corresponding engineering plastic strains prior to necking.

On the basis of this information, what engineering stress (in MPa) is necessary to produce an engineering plastic strain of 0.250
Engineering stress (MPa) Engineering strain
203 0.160
224 0.289
Engineering
1 answer:
kirza4 [7]2 years ago
7 0

Answer:

203.0160

Explanation:

Because you add then subtract then multiply buy 7 the subtract then divide then you add that to the other numbers you got than boom

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What is matrix ? answer plzzz 27 point you got answer​
HACTEHA [7]

Answer:

A matrix is a convenient and useful way of representing a graph to a computer. ... Matrices lend themselves easily to mechanical manipulations. Besides, many known results of matrix algebra can be readily applied to study the structural properties of graphs from an algebraic point of view.

4 0
3 years ago
Read 2 more answers
A company specification calls for a steel component to have a minimum tensile strength of 1240 MPa. Tension tests are conducted
Pavlova-9 [17]

Answer:

a) The minimum acceptable value is 387.5 HV using Vickers hardness test.

b) The minimum acceptable value is 39.4 HRC using Rockwell C hardness test.

Explanation:

To get the tensile strength of a material from its hardness, we multiply it by an empirical constant that depends on things like yield strength, work-hardening, Poisson's ratio and geometrical factors. The incidence of cold-work varies this relationship.

According to DIN 50150 (a conversion table for hardness), the constant for Vickers hardness is ≈ 3.2 (an empirical approximate):

\mbox{Tensile strength}=HV*3.2\\\\HV  = \frac{\mbox{Tensile strength}}{3.2} =\frac{1240}{3.2}=387.5

According to DIN 50150, the constant for Rockwell C hardness test is ≈31.5 around this values of tensile strength:

\mbox{Tensile strength}=HRC*31.5\\\\HRC  = \frac{\mbox{Tensile strength}}{31.5} =\frac{1240}{31.5}=39.4

8 0
3 years ago
A proposed piping and pumping system has 20-psig static pressure, and the piping discharges to atmosphere 160 ft above the pump.
larisa86 [58]

Answer: (B) 100

Explanation:

Given that;

Pstatic = 20 psig , hz = 160ft, hf = 20ft

Now total head will be;

T.h = hz + hf

T.h= 160 + 20

T.h = 180ft

Minimum pressure = Psatic + egh

we know that specific weight of water is 62.4 (lb/ft3)

so

P.min = (20 bf/in² ) + (62.4 b/ft³ × 180 fr

P.min = (20 bf/in² ) + ( 62.4 × 180 × 1 ft²/144 in²)

P.min = 20 + 78

P.min = 98 lbf/in²

Therefore the minimum pressure rating (psi) of the piping system is most nearly B) 100

7 0
3 years ago
Which is the required type of fire extinguisher for standard naval vessels
Bess [88]

Answer:

Mentioned below are the required types of fire extinguishers for standard naval vessels:

  1. Soda Acid Fire Extinguisher
  2. Water Extinguisher
  3. Foam Extinguisher – Chemical and Mechanical
  4. Carbon Dioxide Extinguisher
  5. Dry Powder Extinguisher

Explanation:

A fire extinguisher is a functioning fire insurance gadget used to douse or control little fires, regularly in crisis circumstances. It isn't planned for use on a wild fire, for example, one which has arrived at the roof, jeopardizes the client (i.e., no way out course, smoke, blast danger, and so on.), or in any case requires the mastery of a fire unit. Ordinarily, a fire extinguisher comprises of a hand-held barrel shaped weight vessel containing an operator that can be released to stifle a fire. Fire extinguishers made with non-round and hollow weight vessels likewise exist however are less normal.

A naval vessel is a military boat (or in some cases pontoon, contingent upon arrangement) utilized by a naval force. Naval boats are separated from non military personnel delivers by development and reason. By and large, naval boats are harm versatile and furnished with weapon frameworks, however combat hardware on troop transports is light or non-existent. Naval vessel is planned fundamentally for naval fighting are named warships, rather than help (assistant boats) or shipyard activities.

3 0
3 years ago
Design a PI controller to improve the steady-state error. The system should operate with a damping ratio of 0.8. Compute the ove
blondinia [14]

Answer:

The MATLAB Code for this PI Controller will be:

Kp = 350;

Ki = 300;

Kd = 50;

C = pid(Kp,Ki,Kd)

T = feedback(C*P,1);

t = 0:0.01:2;

step(T,t)

Explanation:

When you are designing a PID controller for a given system, follow the steps shown below to obtain a desired response.

Obtain an open-loop response and determine what needs to be improved

Add a proportional control to improve the rise time

Add a derivative control to reduce the overshoot

Add an integral control to reduce the steady-state error

Adjust each of the gains $K_p$, $K_i$, and $K_d$ until you obtain a desired overall response.

The further explanation is attached in the Word File.

Download docx
5 0
3 years ago
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