A lot of teachers don't teach SohCahToa anymore! this acronym will really help you. I'd suggest looking up how to use it, it'll make trigonometry WAY easier!
Answer:
77.76 times
Step-by-step explanation:
The average distance of Neptune from the sun
= 4.503 × 10
⁹ k
m
.
and Mercury = 5.791 × 10
⁷ k
m
.
Hence neptune is ( 4.503 × 10
⁹) ÷ (5.791
×
10
⁷ ) times farther from the sun than mercury
i.e.( 
) × 10⁹⁻⁷ times
=
0.7776 × 10
² times
=
77.76 times.
Answer:
Part 1) 
Part 2) 
Part 3) 
Step-by-step explanation:
step 1
Find the measure of length side FG
In the right triangle EFG
we know that
----> by SOH (opposite side divided by the hypotenuse)
substitute the given values
step 2
Find the measure of length side EF
In the right triangle EFG
we know that
----> by CAH (adjacent side divided by the hypotenuse)
substitute the given values
step 3
Find the measure of angle G
we know that
---> by complementary angles in a right triangle
For perpendicular lines, the slopes are negative reciprocals of one another. Therefore, the slope of QC = 3/2
Using this into the formula of slope:
3/2 = (y + 6) / (-1 + 3)
y = -9
If the slope of CD is 2/3, then y works out to be -3.
Answer:
Step-by-step explanation:
Answer is C
We need to find oblique asymtotes of f(x).
Oblique asymtotes form when degree of numerator is greater than denominator.
First we find the degree of numerator and denominator for f(x)
Degree of f(x) at numerator = 2
Degree of f(x) at denominator = 1
So, one oblique asymtote form.
First we divide by
Quoetient of the above division would be oblique asymtote.
First we find the degree of numerator and denominator for f(x)
Degree of f(x) at numerator = 2
Degree of f(x) at denominator = 1
So, one oblique asymtote form.
