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3 years ago

Is 0.6 a rational number

Mathematics

2 answers:

astraxan [27]3 years ago

8 0

Answer:

The decimal 0.6 is a rational number. It is the decimal form of the fraction 6/10.

hoa [83]3 years ago

4 0

Answer:

Yes. 0.6 is a rational number.

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3 years ago

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Zack has a old car. He wants to sell it for 60% off the current price. The market price is $500. How much money would he receive

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(Hope this works!!)

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3 years ago

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3 years ago

4. Neelam's annual income is Rs. 288000. Her annual savings amount

Vikki [24]

Answer:

The ratio of her savings to expenditure 1 : 7.

Step-by-step explanation:

Given:

Neelam's annual income is Rs. 288000.

Her annual savings amount to Rs. 36000.

Now, to get the ratio of her savings to her expenditure:

So, we get the expenditure first:

Expenditure = Income - Savings.

Expenditure = 288000 - 36000 = Rs. 252000.

Now, the ratio of savings to expenditure:

$\frac{Savings}{Expenditure} =\frac{36000}{252000}$

$\frac{Savings}{Expenditure} =\frac{1}{7}$

Thus, Savings:Expenditure = 1:7.

Therefore, the ratio of her savings to expenditure 1 : 7.

3 0

4 years ago

The acceleration of an object (in m/s^2) is given by the function a(t) = 9 sin(t). The initial velocity of the object is v(0) =

pentagon [3]

a) Acceleration is the derivative of velocity. By the fundamental theorem of calculus,

$v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du$

so that

$v(t)=\left(-11\frac{\rm m}{\rm s}\right)+\int_0^t9\sin u\,\mathrm du$

$\boxed{v(t)=-\left(2+9\cos t)\right)\frac{\rm m}{\rm s}}$

b) We get the displacement by integrating the velocity function like above. Assume the object starts at the origin, so that its initial position is $s(0)=0\,\mathrm m$ . Then its displacement over the time interval [0, 3] is

$s(0)+\displaystyle\int_0^3v(t)\,\mathrm dt=-\int_0^3(2+9\cos t)\,\mathrm dt=\boxed{-6-9\sin3}$

c) The total distance traveled is the integral of the absolute value of the velocity function:

$s(0)+\displaystyle\int_0^3|v(t)|\,\mathrm dt$

$v(t)$ for $0\le t$ and $v(t)\ge0$ for $\cos^{-1}\left(-\frac29\right)\le t\le3$ , so we split the integral into two as

$\displaystyle\int_0^{\cos^{-1}\left(-\frac29\right)}-v(t)\,\mathrm dt+\int_{\cos^{-1}\left(-\frac29\right)}^3v(t)\,\mathrm dt$

$=\displaystyle\int_0^{\cos^{-1}\left(-\frac29\right)}(2+9\cos t)\,\mathrm dt-\int_{\cos^{-1}\left(-\frac29\right)}^3(2+9\cos t)\,\mathrm dt$

$\displaystyle=\boxed{2\sqrt{77}-6+4\cos^{-1}\left(-\frac29\right)-9\sin3}$

4 0

3 years ago

Is 0.6 a rational number​

Is 0.6 a rational number