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2 years ago

Hai! What Is 4 Squared???

Mathematics

2 answers:

Nitella [24]2 years ago

4 0

Answer:

Step-by-step explanation:

$x^{2}$ = $x$ multiplied by $x$

so $4^{2}$ = 16

lakkis [162]2 years ago

4 0

Answer:

Step-by-step explanation:

4 squared should look like this:

4²

That means we just multiply 4 twice:

4 x 4

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Solve the following for w: P=2l+2w

exis [7]

Answer:

w = P/2 - 1

Step-by-step explanation:

Can I have brainliest?

8 0

3 years ago

I need help with this question

nata0808 [166]

I don't know if you've learnt this, but there's something called the KFC rule (you use it when dividing fractions), so k basically stands for keep (so you keep the first fraction), f stands for flip (so you flip the second fraction) and c stand for change (you change the division sign to a multiplication sign)

So you get

5/20*11/5

55/100

which is 11/20

so, an answer of 11/20 would make Quintin correct

5 0

3 years ago

Read 2 more answers

The students who run the school store ordered 1440 pencils. They are putting them in packages of 6 pencils. About how many packa

chubhunter [2.5K]

Well I don't get what the other parts of the question is asking, but they can make 240 packs of pencils.

7 0

4 years ago

12. What is the slope of the line =3x + 5? 5 3 -5 -3

Reika [66]

Answer:

3, 3x+5

Step-by-step explanation:

DIFFERENTIATE W.R.T. X

EVALUATE

3x+5

4 0

2 years ago

Find equations of the spheres with center(1, −1, 6)that touch the following planes.a) xy-planeb) yz-planec) xz-plane

Misha Larkins [42]

Given :

Center of sphere , C( 1 , -1 , 6 ) .

To Find :

Find equations of the spheres with center (1, −1, 6) that touch the following planes.a) xy-plane b) yz-plane c) xz-plane .

Solution :

Distance of the point from xy-plane is :

d = 6 units .

So , equation of circle with center C and radius 6 units is :

$(x-1)^2+(y-(-1))^2+(z-6)^2=6^2\\\\(x-1)^2+(y+1)^2+(z-6)^2=36$

Distance of point from yz-plane is :

d = 1 unit .

So , equation of circle with center C and radius 1 units is :

$(x-1)^2+(x+1)^2+(z-6)^2=1^2\\\\(x-1)^2+(x+1)^2+(z-6)^2=1$

Distance of point from xz-plane is :

d = 1 unit .

So , equation of circle with center C and radius 1 units is :

$(x-1)^2+(x+1)^2+(z-6)^2=1^2\\\\(x-1)^2+(x+1)^2+(z-6)^2=1$

Hence , this is the required solution .

4 0

3 years ago