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Tems11 [23]
3 years ago
11

A beverage manufacturer wants to increase the solubility of carbon dioxide (CO2) in its carbonated drinks.

Physics
1 answer:
Brut [27]3 years ago
6 0

D. Decreasing its temperature

Explanation:

Decreasing the temperature of the carbon dioxide gas to be dissolved in the carbonated drink will most likely increase the solubility of the gas in the drink.

Temperature has considerable effects on the solubility of gases in liquids.

  • Dissolution involves the surrounding of ions by water molecules, in this case, the carbon dioxide gas is to be surrounded by the liquid beverage medium.
  • Increasing pressure increases the rate at which gases are soluble. At high pressure, the gases are brought more in contact with the liquid medium.
  • Decreasing temperature aids gas solubility.
  • If the temperature of gases are increased,  they will not want to stay in solution as they gain a high amount of kinetic energy.
  • Therefore, it will increase their randomness and the urge to leave the solution.
  • Decrease in temperature and increase in pressure makes gas solubility to be fast.  

Learn more:

Rate of chemical reactions brainly.com/question/6281756

#learnwithBrainly

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What does the electric field strength tell about the electric firld?
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Which formula represents final velocity of an object with average acceleration?
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A tuning fork vibrating at 508 Hz falls from rest and accelerates at 9.80 m/s^2. How far below the point of release is the tunin
JulijaS [17]

Answer:

Explanation:

given,

tuning fork vibration = 508 Hz

accelerates = 9.80 m/s²

speed of sound = 343 m/s

observed frequency = 490 Hz

f_s = f(\dfrac{v}{v-(-v_s)})

f_s = f(\dfrac{v}{v+v_s})

v_s = v[\dfrac{f_s}{f_o}-1]

      = 343[\dfrac{508}{490}-1]

      v_s=12.6 m/s

distance the tunning fork has fallen

y_1=\dfrac{v^2}{2a_y}

     =\dfrac{12.6^2}{2\times 9.8}

     =8.1 m

now, time required for the observed will be

t = \dfrac{8.1}{343} = 0.023 s

now, for the distance calculation

y_2 = u\ t + \dfrac{1}{2}at^2

  = 12.6\times 0.023 +\dfrac{1}{2}\times 9.8 \times 0.023^2

  =0.293 m

total distance

 = 8.1 + 0.293 = 8.392 m

3 0
3 years ago
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