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Anton [14]
4 years ago
7

An Earth satellite needs to have its orbit changed so the new orbit will be twice as far from the center of Earth as the origina

l orbit. The new orbital period will be twice as long as the original period. O true O false
Physics
1 answer:
horsena [70]4 years ago
5 0

Answer:

False.

Explanation:

From Kepler's Third Law of plenetary motion, we know that:

<em>"The square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit."</em>

Or, as expressed in mathematical terms:

\frac{a^3}{T^2}=constant, where <em>a</em> is the semi-major axis of the orbit (the distance from the center), and <em>T </em>is the orbital period of the satellite.

From this expression we can clearly see that if the orbit's semi-major axis is doubled, orbital period will be \sqrt{8} times longer to compensate the variation.

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Why do remote controls for TV’s use infrared waves to communicate?
Delvig [45]

Answer:  An IR remote (also called a transmitter) uses light to carry signals from the remote to the device so it can be controlled. It emits pulses of invisible infrared light that correspond to specific binary codes. These codes represent commands, such as power on, volume up, or channel down.

Explanation:

3 0
3 years ago
When a point charge of q is placed on one corner of a square, an electric field strength of 2 N/C is observed at the center of t
bearhunter [10]

Answer:

Explanation:

Net electric field at the centre will be zero .

Since all the charges are equal and they all are symmetrically situated around the centre . So the electric field produced by each will cancel  out each other and hence the resultant electric field will be zero . It happens because electric field is a vector quantity and therefore it adds up vectorially . All the four electric field will form two pairs , in each pair electric fields are acting in opposite direction . So they all cancel out to zero .

3 0
3 years ago
Steel train rails are laid in 12.0-m-long segments placed end to end. The rails are laid on a winter day when their temperature
Yanka [14]

Answer:

a) Space = 6.05 x 10^{-3} m = 0.605 cm

b) Stress= -100.8 x 10^{6} Pa

Explanation:

<em>1) Data Given</em>

L = 12 m , T_i = -9 C \degree, T_f = 33 C \degree

<em>2) Calculate the space using Linear thermal expansion formula</em>

We need to use Linear thermal expansion formula since the space created would be a change on 1 dimension, the increase of the temperature will increase the length of the steel.  The formula is given by:

\Delta L = L_i \alpha_{steel} \Delta T

We have everything except the \alpha_{steel} , so we look for this on a book and we find that \alpha_{steel} = 1.2 x 10^{-5} C^{-1}, so we can replace.

\Delta L = 12 m (1.2 x 10^{-5} C^{-1}) (33 C \degree -(-9 C \degree)) = 12 m (1.2 x 10^{-5} C^{-1}) 42 C \degree =6.048 x 10^{-3} m = 0.6048cm

<em>3) Calculate the stress of the steel </em>

The Stress is the ratio of applied force F to a cross section area - defined as

\sigma = \frac{F_n}{A}

Since we don't have the force and the Area, we need to look for another way to find the stress.

For this we can use the concept called Young's Modulus, defined as : "the mechanical property that measures the stiffness of a solid material", and the formula for this is given by:

Y =\frac{F L}{A \Delta L} (1)

Solving \frac{F}{A} from the previous formula we have this:

\frac{F}{A}  = (Y  Δ L)/L  (2)

From the <em>Linear thermal expansion formula</em> we can solve like this

\frac{\Delta L}{L} =  α  ΔT  (3)

And replacing equation (3) into equation (2) we have:

\frac{F}{A}  = Y α ΔT (4)

We have that the Young's Modulus for the steel is 20x10^{10} Pa, so replacing into equation (4)

\frac{F}{A} = 20x10^{10} Pa (1.2x10^-5 C^-1) (42C) = 100.8 *10^{6} Pa  

That represent the absolute value for the Stress, the sign on this case would be negative since there is a compression.

3 0
4 years ago
Explain why it is important to identify a reference point for any description of motion.
Leya [2.2K]

A reference is critical because it determines how much motion has occurred. You can't determine how much an objected has moved if you don't know where it came from.

3 0
3 years ago
Read 2 more answers
A golfer badly misjudges a putt, sending the ball only one-quarter of the distance to the hole. The original putt gave the ball
IRISSAK [1]

Answer:

v = 2 v₀

Explanation:

For this exercise we will use the relationship between work and the change in kinetic energy

          W = ΔK

Where the work is of the friction force, which is always opposed to the movement whereby the angle is 180º

          W = - fr x

The distance for the first case is

         x = 1/4 L

         

We substitute

       -fr ¼ L = ½ m v₀²

        fr L = 2 m v₀²

In the second case, the new speed takes the ball the entire distance

        x = d

        -fr L = ½ m v²

     

We equal the two equations

        2 m v₀² = ½ m v²

        v² = 4 v₀²

        v = 2 v₀

3 0
4 years ago
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