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Anton [14]
3 years ago
7

An Earth satellite needs to have its orbit changed so the new orbit will be twice as far from the center of Earth as the origina

l orbit. The new orbital period will be twice as long as the original period. O true O false
Physics
1 answer:
horsena [70]3 years ago
5 0

Answer:

False.

Explanation:

From Kepler's Third Law of plenetary motion, we know that:

<em>"The square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit."</em>

Or, as expressed in mathematical terms:

\frac{a^3}{T^2}=constant, where <em>a</em> is the semi-major axis of the orbit (the distance from the center), and <em>T </em>is the orbital period of the satellite.

From this expression we can clearly see that if the orbit's semi-major axis is doubled, orbital period will be \sqrt{8} times longer to compensate the variation.

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goldfiish [28.3K]
Palm of your hand should be the correct answer if i remember correctly
3 0
3 years ago
A spring is 6.0cm long when it is not stretched, and 10cm long when a 7.0N force is applied. What force is needed to make it 20c
Artist 52 [7]

Answer:

Approximately 25\; {\rm N} (assuming that this spring is ideal.)

Explanation:

The displacement of a spring is the new length of the spring relative to the original length.

For example:

  • When the 6.0\; {\rm cm}-spring in this question is stretched to 10\; {\rm cm}, the displacement is x = (10\; {\rm cm} - 6.0\; {\rm cm}).
  • Likewise, if this spring is stretched to 20\; {\rm cm}, the displacement would be (20\; {\rm cm} - 6\; {\rm cm}).

If this spring is ideal, the force on the spring would be proportional to the displacement of the spring. In other words, if a force of F_{\text{a}} displaces this spring by x_{\text{a}}, while a force of F_{\text{b}} displaces this spring by x_{\text{b}}, then:

\displaystyle \frac{F_{\text{a}}}{x_{\text{a}}} = \frac{F_{\text{b}}}{x_{\text{b}}}.

In this question, it is given that a force of F_{\text{a}} = 7.0 \; {\rm N} would stretch this spring by x_{\text{a}} = (10\; {\rm cm} - 6.0\; {\rm cm}). Thus, the force F_{\text{b}} required to stretch this spring by x_{\text{a}} = (20\; {\rm cm} - 6.0\; {\rm cm}) would satisfy:

\displaystyle \frac{7.0\; {\rm N}}{10\; {\rm cm} - 6.0\; {\rm cm}}= \frac{F_{\text{b}}}{20\; {\rm cm} - 6.0\; {\rm cm}}.

Rearrange and solve for F_{\text{b}}:

\begin{aligned} F_{\text{b}} &= \frac{7.0\; {\rm N}}{10\; {\rm cm} - 6.0\; {\rm cm}} \, (20\; {\rm cm} - 6.0\; {\rm cm}) \\ &\approx 25\; {\rm N}\end{aligned}.

7 0
2 years ago
This is a form of energy representing the motion of the molecules which make up an object. A. Thermal Energy B. Kinetic Energy C
bija089 [108]

Answer:

Kinetic energy.

Explanation:

  • There are many kinds of energy. Some of them are kinetic energy, potential energy, thermal energy etc.
  • The energy that shows the motion of the object is called its kinetic energy.
  • Also, the sum of kinetic energy and the gravitational potential energy is called mechanical energy.
  • Out of the given options, kinetic energy is the form of energy that represents the motion of the molecules which make up an object.
  • Hence, the correct option is (B).
4 0
3 years ago
5. Describe the shape of the waveform in the secondary coil for a sine, square and triangle wave in the primary coil. How does t
Volgvan

Answer:

When primary coil is exited by sin wave,this will result in sin wave in secondary coil as well.According to law,flux induced in the secondary coil will have same waveform as in the primary coil.

5 0
3 years ago
In which one of the following situations is zero net work done? A) A ball rolls down an inclined plane. B) A physics student str
lidiya [134]

Answer:

Option D

Explanation:

The work done can be given by the mechanical energy used to do work, i.e., Kinetic energy and potential energy provided to do the work.

In all the cases, except option D, the energy provided to do the useful work is not zero and hence work done is not zero.  

In option D, the box is being pulled with constant velocity, making the acceleration zero and thus Kinetic energy of the system is zero. Hence work done in this case is zero.

6 0
3 years ago
Read 2 more answers
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