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aleksklad [387]
3 years ago
15

Monochromatic light falls on two very narrow slits 0.047 mm apart. Successive fringes on a screen 6.60 m away are 8.9 cm apart n

ear the center of the pattern.
Determine the wavelength and frequency of the light.
Physics
1 answer:
Svet_ta [14]3 years ago
6 0

Answer::

   \lambda  =  634 nm

  f =  4.73 *10^{14} \  Hz

Explanation:

From the question we are told that

      The  distance of separation is  d =  0.047 \ mm =  0.047 *10^{-3} \ m

       The  distance of the screen is  D =  6.60 \ m

      The  width of the fringe is y  =  8.9 \ cm  =  0.089 \ m

     

Generally the width of the width of the fringes is mathematically represented as

          y  = \frac{\lambda  *  D }{d }

=>       \lambda  =  \frac{y *  d }{D }

=>      \lambda  =  \frac{ 0.089  *   (0.047 *10^{-3}) }{6.60  }

=>    \lambda  =  634 *10^{-9}

=>  \lambda  =  634 nm

Generally the speed of light is mathematically represented as

         c  =  f * \lambda

=>       f=  \frac{ c}{\lambda }

=>         f=  \frac{ 3.0 *10^{8}}{634 *10^{-9}}

=>     f =  4.73 *10^{14} \  Hz

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Answer:

W = (F1 - mg sin θ) L,   W = -μ  mg cos θ L

Explanation:

Let's use Newton's second law to find the friction force. In these problems the x axis is taken parallel to the plane and the y axis perpendicular to the plane

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Let's use trigonometry to find the components of the weight

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Work is defined by

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        W = -fr x

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Another way to calculate is

         fr = μ N

         fr = μ W cos θ

the work is

         W = -μ  mg cos θ L

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