The answer for the following problem is described below.
<em><u> Therefore the standard enthalpy of combustion is -2800 kJ</u></em>
Explanation:
Given:
enthalpy of combustion of glucose(Δ
of 
) =-1275.0
enthalpy of combustion of oxygen(Δ of 
) = zero
enthalpy of combustion of carbon dioxide(Δ of 
) = -393.5
enthalpy of combustion of water(Δ of 
) = -285.8
To solve :
standard enthalpy of combustion
We know;
Δ = ∈Δ (products) - ∈Δ (reactants)
(s) +6 (g) → 6 (g)+ 6 (l)
Δ = [6 (-393.5) + 6(-285.8)] - [6 (0) + (-1275)]
Δ = [6 (-393.5) + 6(-285.8)] - [0 - 1275]
Δ = 6 (-393.5) + 6(-285.8) - 0 + 1275
Δ = -2361 - 1714 - 0 + 1275
Δ =-2800 kJ
<em><u> Therefore the standard enthalpy of combustion is -2800 kJ</u></em>
D. One chimp cleaning and grooming the hair of another chimp
Answer:
yes it is dangerous
Explanation:
Water reactive substances are dangerous when wet because they undergo a chemical reaction with water.
Redox reaction is the reduction and oxidation reaction. It is a chemical reaction that involves a transfer of electrons. It can mean loss of oxygen (oxidation) or gain of electrons (reduction). Oxydation is the process of where a sustance loses electrons, gains an oxygen atom/s, loses a hydrogen atom/s. reduction is the opposite.
In a redox reaction, one of the reactants must release electrons.
Answer:
Water is a polar solvent
Explanation:
We must know that pure dry hydrogen chloride gas does not show any acidic property.
In fact, when hydrogen chloride is dissolved in water, it breaks up into H3O^+ ions and Cl^- ions. This is possible because water is a polar solvent and assists the ionization of HCl.
In nonpolar solvents such as benzene, hydrogen chloride gas is not ionized hence it does not show any acidic property in a benzene solution.
