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igor_vitrenko [27]
3 years ago
5

NaClO4/ HCIO4 is a buffer system ​

Chemistry
1 answer:
Doss [256]3 years ago
7 0
No it’s not a buffer system HClO4 is a strong acid and NaClO4 is it’s corresponding salt

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a baseball player hits a baseball with a bat.The mass of the ball is 0.25kg.The ball accelerates at 200m/s2
34kurt

Answer:

50N

Explanation:

Force (N) = mass (kg) × acceleration (m/s²)

0.25kg times 200m/s² = 50N

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3 years ago
Use significant digits to express the weight of a 150.0 lb person in kilograms ( 1 lb = 453.6 g)
slamgirl [31]

Answer:

150.0 = 68.038856

Explanation:

kilograms

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2 years ago
Describe how to make a buffer solution using a strong base and one other reagent.
svet-max [94.6K]
A buffer is a solution of weak acid and conjugate base or weak base and conjugate acid used to resist pH change with added solute. <span />
4 0
3 years ago
QUESTION 3 Consider a solution containing 0.80 M NaF and 0.80 M HF. Calculate the moles of HF and the concentration of HF after
Lisa [10]

Answer:

0.056moles HF and 0.70M

Explanation:

When a strong acid is added to a buffer, the acid reacts with the conjugate base.

In the system, NaF and HF, weak acid is HF and conjugate base is NaF. The reaction of NaF with HCl (Strong acid) is:

NaF + HCl → HF + NaCl

Initial moles of NaF and HF in 60.0mL of solution are:

NaF:

0.0600L × (0.80mol / L)= 0.048 moles NaF

HF:

0.0600L × (0.80mol / L)= 0.048 moles HF

Then, the added moles of HCl are:

0.0200L × (0.40mol / L) = 0.008 moles HCl.

Thus, after the reaction, moles of HF produced are 0.008 moles + the initial 0.048moles of HF, moles of HF are:

<em>0.056moles HF</em>

<em></em>

In 20.0mL + 60.0mL = 80.0mL = 0.0800L, molarity of HF is:

0.056mol HF / 0.0800L = <em>0.70M</em>

6 0
3 years ago
If 3.0 moles of A and 4.0 moles of B react according to the hypothetical reaction below, how many moles of the excess reactant w
blondinia [14]
1 mol of A should be left over
5 0
3 years ago
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