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The formula of the hydrate = CuSO₄• 3H₂O
<h3>Further explanation</h3>
Given
4.175 grams sample CuSO₄• xH₂O
3.120 grams anhydrous compound CuSO₄
Required
The formula
Solution
mass of H₂O driven off :
= 4.175 - 3.12
= 1.055 g
MW CuSO₄ = 159.5 g/mol
MW H₂O = 18 g/mol
mol ratio of CuSO₄ : H₂O :
= 3.12/159.5 : 1.055/18
= 0.01956 : 0.05861
= 1 : 3
Answer:
cis-1-tert-butyl-3-methylcyclohexane will have a higher percentage of the diequatorial-substituted conformer when compared with the diaxialsubstituted conformer.
Explanation:
The two compound contain or have high stability with the substituent group is at equatorial position but the tert-betyl group in cis-1-tert-butyl-3-methylcyclohexane is larger than the methyl group in trans-1,4-dimethylcyclohexane.
Thus, the equatorial position will be more favorable for the substituent group in the cis-1-tert-butyl-3-methylcyclohexane, therefore having higher percentage of the diequatorial substituted conformer compared with that of diaxial-substituted conformer.
Mendeleev organized his periodic table in order of increasing atomic number in 1869.
The percentage of water of crystallization in blue vitriol is 36.07%.
M(H₂O) = 2Ar(H) + Ar(O) x g/mol
M(H₂O) = 2 + 16 x g/mol
M(H₂O) = 18 g/mol; molar mass of water
M(CuSO₄·5H₂O) = Ar(Cu) + Ar(S) + 4Ar(O) + 5Mr(H₂O) x g/mol
M(CuSO₄·5H₂O) = 63.5 + 32 + 64 + 90 x g/mol
M(CuSO₄·5H₂O) = 249.5 g/mol; molar mass of copper sulphate pentahydrate
The percentage of water: 5M(H₂O) / M(CuSO₄·5H₂O) x 100%
The percentage of water: 90 g/mol / 249.5 g/mol x 100%
The percentage of water = 36.07%
More about blue vitriol: brainly.com/question/8895853
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