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satela [25.4K]
3 years ago
14

PLEASE HELP

Physics
1 answer:
Zarrin [17]3 years ago
3 0

Answer:

850.63 kg/m^3

Explanation:

p=pgh

4910 = pxq .8x 0.589

p= 850.63 kg/m^3

this is what i got

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A person has a mass of 60 kg. What is the person’s weight in Newtons and in pounds?
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Answer:

137.2 in pounds and in Newton's it's 588.399

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Consider the following quantities: (1) mass, (2) velocity, (3) charge, and (4) magnetic field strength. Upon which of these quan
DENIUS [597]

Answer:

2,3,4

Explanation:

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3 years ago
The deck of a bridge is suspended 235 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of
Aleks04 [339]

Answer:

(a) 1, average velocity = -65.6 m/s

   2, average velocity = -64.8 m/s

   3, average velocity = -64.16 m/s

(b) The instantaneous velocity is -96 m/s

Explanation:

(a)

Average velocity is given  by;

y(t_2,t_1) = \frac{y(t_2) - y(t_1)}{t_2-t_1}

(1)

y(2.1,2) = \frac{(235-16*2.1^2) - (235-16*2^2)}{2.1-2}\\\\ y(2.1,2) = -65.6 \ m/s

(2)

y(2.05,2) = \frac{(235-16*2.05^2) - (235-16*2^2)}{2.05-2}\\\\ y(2.05,2) = -64.8 \ m/s

(3)

y(2.01,2) = \frac{(235-16*2.01^2) - (235-16*2^2)}{2.01-2}\\\\ y(2.01,2) = -64.16 \ m/s

b. y = 235 - 16t²

The instantaneous velocity is given by;

v = dy /dt

dy / dt = -32t

when t = 3 s

v = -32(3)

v = -96 m/s

5 0
4 years ago
A box that is resting on an inclined plane has what forces acting on it
miskamm [114]

A box residing on an inclined plane has following forces:

In the X- direction

Mg sin (theta) = horizontal  component of weight of the box

f = Frictional force = uN , u = frictional factor, N= mg

In the Y- direction

upward force = Normal reaction of the box = mg

downward force = mg cos(theta) = vertical component of weight of the box


5 0
4 years ago
A swimming pool is circular with a 30-ft diameter. The depth is constant along east-west lines and increases linearly from 5 ft
Schach [20]

Answer : The volume of water in the pool is, 2473 ft³

Explanation :

First we have to calculate the average depth.

Given:

Diameter = 30 ft

Depth range : 1 to 6 ft linearly

average depth =

Now we have to calculate the volume of water in the pool.

Volume = area × average depth

V = π × (radius)² × 3.5

V = π × (30/2)² × 3.5

V = π × (15)² × 3.5

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V = 3.14 × 225 × 3.5

V = 2472.75 ft³ ≈ 2473 ft³

Therefore, the volume of water in the pool is, 2473 ft³

3 0
4 years ago
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