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3 years ago

A train started its journey at 9:00. Its average speed between

Physics

1 answer:

Vera_Pavlovna [14]3 years ago

5 0

Answer:

Explanation:

In the four hours before 13:00 the train traveled 4(80) = 320 km.

It needs to travel another 4(320) = 1280 km in the next 21:00 - 13:00 = 8 hrs.

1280 / 8 = 160 km/hr

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Why is the efficiency of a machine always less than 100%?

never [62]

Answer:The percentage of the work input that becomes work output is the efficiency of a machine. Because there is always some friction, the efficiency of any machine is always less than 100 percent.

Explanation:

Sub to rockingcoolstyle15 on yt

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3 years ago

Will get Brainlest 5 star and heart looking for someone who knows 7 grd science flvs work dm and friend

Makovka662 [10]

ANSWER:
C

EXPLANTION:
The earths crust is the toppest layer of Earth, so that elimates option A and B.

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3 years ago

If an object looses electrons, then have been transferred

slava [35]

If a neutral object loses some electrons, then it will possess more protons

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3 years ago

On Earth, the number flux of solar neutrinos from the p-p chain is:

Nataly [62]

Answer:

Explanation:

The volume of the tank = 50 kton

50 kton = 5 × 10⁷ kg

Since 18 grams of water will contain: 10 electrons × 6.023 × 10²³

Then;

5× 10⁷ kg will contain $( \dfrac{5 \times 10^7 \times 10^3}{18}) \times 10 \times 6.023 \times 10^{23}$

= 1.67 × 10³⁴ electrons

(b)

Suppose:

$f_{neutrino} = \dfrac{2f_o}{26.2 MeV} = 6.7\times 10^{10} \ s^{-1} cm^{-2}$

Then;

10⁻⁶ of $f_{neutrino} = 6.7 \times 10^{10} \times 10^{-6} \ s^{-1} cm^{-2}$

$=6.7 \times 10^{4}\ s^{-1} cm^{-2}$

Thus, the number of high energy neutrinos which will interact with water is:

= $6.7 \times 10^4 \times \sigma$

= $6.7 \times 10^4 \times 10^{-43}$

= $6.7 \times 10^{-39} s^{-1}$

For 1.67 × 10³⁴ electrons, the detection rate is:

$6.7 \times 10^{-39} \times 1.67 \times 10^{34}$

$= 11.19 \times 10^{-5} \ s^{-1}$

= 9.668 per day

3 0

3 years ago

A 75 kg man and a 100. Kg woman are playing tug of war on a frictionless surface. The man accelerates toward the woman at 2.0 m/

Artemon [7]

Complete Question

A 75 kg man and a 100. Kg woman are playing tug of war on a frictionless surface. The man accelerates toward the woman at 2.0 m/s2.How much force does she use to pull on the rope

Answer:

The value is $F = 150 \ N$