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Sav [38]
3 years ago
13

6+ ? +12-2= 30 a) 10 b) 11 c) 14 d) 12

Mathematics
2 answers:
balandron [24]3 years ago
6 0

Answer:

c

Step-by-step explanation:

12 - 2 = 10

10 + 6 = 16

30 = 16 + x

x = 30 - 16

x = 14

Vsevolod [243]3 years ago
5 0

Answer:

c) 14

Step-by-step explanation:

Solution:

Let the other number be x

Now,

6+x+12-2=30

6+x+10=30

x+16=30

x=30-16

x=14

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The histogram below shows the heights, rounded to the nearest inch, of the members of the Oak High School basketball team. A. 1
Elan Coil [88]

Answer:

Range of player's height = 9 inch

Step-by-step explanation:

Given:

Number of players    Height range

4                                     66-67

8                                     68 -69

14                                    70-71

9                                     72-73

1                                      74-75

Find:

Range of player's height

Computation:

Range = Maximum value - Minimum Value

Range of player's height = Maximum height of a player - height of a player

Range of player's height = 75 inch - 66 inch

Range of player's height = 9 inch

5 0
3 years ago
Solve using any method. Choose the correct ordered pair.
lesya692 [45]

Answer:

C

Step-by-step explanation:

-2 + 7 = 5

7 0
4 years ago
Read 2 more answers
Y=3x+4 and crosses through the point (1,8)
erma4kov [3.2K]
The answer is  your equation does not pass though the point (1,8)
3 0
3 years ago
What is the domain and range of f(x)=4^x-8
gladu [14]

If the function is: f(x) = 4^x     - 8

D = {XeR}
R = {YeR|Y≥0}


if the function is: <span>f(x)=4^(x-8)

</span>D = {XeR}
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8 0
3 years ago
What are the endpoint coordinates for the midsegment of △BCD that is parallel to BC?
natulia [17]

Answer:

<em>The endpoint coordinates for the mid-segment are:  (-2,-1) and (1,0)</em>

Step-by-step explanation:

According to the given diagram, the coordinates of the vertices of \triangle BCD are:   B(-3,1), C(3,3) and D(-1,-3)

Now, the endpoints of the mid-segment of \triangle BCD which is parallel to BC will be the mid-points of sides BD and CD.

<u>Formula for the coordinate of mid-point</u> :   (\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}), where (x_{1}, y_{1}) and (x_{2}, y_{2}) are two endpoints.

So, the mid-point of BD will be:  (\frac{-3-1}{2},\frac{1-3}{2})=(\frac{-4}{2},\frac{-2}{2})=(-2,-1)

and the mid-point of CD will be:  (\frac{3-1}{2},\frac{3-3}{2})=(\frac{2}{2},\frac{0}{2})=(1,0)

Thus, the endpoint coordinates for the mid-segment of \triangle BCD that is parallel to BC are  (-2,-1) and (1,0)

4 0
3 years ago
Read 2 more answers
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