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Inga [223]
3 years ago
15

The width of the same paper (given in question1) is measured 3 times using a ruler marked with

Physics
1 answer:
antiseptic1488 [7]3 years ago
3 0

Answer:

60

Explanation:

You might be interested in
A large crate with mass m rests on a horizontal floor. The static and kinetic coefficients of friction between the crate and the
rjkz [21]

Answer:

a) F=\frac{\mu_{k}mg}{cos \theta-\mu_{k}sin \theta}

b) \mu_{s}=\frac{Fcos \theta}{Fsin \theta +mg}

Explanation:

In order to solve this problem we must first do a drawing of the situation and a free body diagram. (Check attached picture).

After a close look at the diagram and the problem we can see that the crate will have a constant velocity. This means there will be no acceleration to the crate so the sum of the forces must be equal to zero according to Newton's third law. So we can build a sum of forces in both x and y-direction. Let's start with the analysis of the forces in the y-direction:

\Sigma F_{y}=0

We can see there are three forces acting in the y-direction, the weight of the crate, the normal force and the force in the y-direction, so our sum of forces is:

-F_{y}-W+N=0

When solving for the normal force we get:

N=F_{y}+W

we know that

W=mg

and

F_{y}=Fsin \theta

so after substituting we get that

N=F sin θ +mg

We also know that the kinetic friction is defined to be:

f_{k}=\mu_{k}N

so we can find the kinetic friction by substituting for N, so we get:

f_{k}=\mu_{k}(F sin \theta +mg)

Now we can find the sum of forces in x:

\Sigma F_{x}=0

so after analyzing the diagram we can build our sum of forces to be:

-f+F_{x}=0

we know that:

F_{x}=Fcos \theta

so we can substitute the equations we already have in the sum of forces on x so we get:

-\mu_{k}(F sin \theta +mg)+Fcos \theta=0

so now we can solve for the force, we start by distributing \mu_{k} so we get:

-\mu_{k}F sin \theta -\mu_{k}mg)+Fcos \theta=0

we add \mu_{k}mg to both sides so we get:

-\mu_{k}F sin \theta +Fcos \theta=\mu_{k}mg

Nos we factor F so we get:

F(cos \theta-\mu_{k} sin \theta)=\mu_{k}mg

and now we divide both sides of the equation into (cos \theta-\mu_{k} sin \theta) so we get:

F=\frac{\mu_{k}mg}{cos \theta-\mu_{k}sin \theta}

which is our answer to part a.

Now, for part b, we will have the exact same free body diagram, with the difference that the friction coefficient we will use for this part will be the static friction coefficient, so by following the same procedure we followed on the previous problem we get the equations:

f_{s}=\mu_{s}(F sin \theta +mg)

and

F cos θ = f

when substituting one into the other we get:

F cos \theta=\mu_{s}(F sin \theta +mg)

which can be solved for the static friction coefficient so we get:

\mu_{s}=\frac{Fcos \theta}{Fsin \theta +mg}

which is the answer to part b.

3 0
4 years ago
Read 2 more answers
The plates of a parallel plate capacitor are separated by d = 1.6 cm. The potential of the negative plate is 0 V, and the potent
yaroslaw [1]

Answer:

The electric field between the plates is 1875 V/m.

Explanation:

Given that,

Separated d=1.6 cm

Potential of negative plate = 0 V

Potential halfway between the plates = 15 V

We need to calculate the total potential

Using formula of potential

V=2\times\text{Potential halfway between the plates}

Put the value into the formula

V=2\times15

V=30\ V

We need to calculate the electric field between the plates

Using formula of electric field

E=\dfrac{V}{d}

E=\dfrac{30}{1.6\times10^{-2}}

E=1875\ V/m

Direction is negative as the field always points from positive  to negative plate

Hence, The electric field between the plates is 1875 V/m.

5 0
3 years ago
if a ball is thrown horizontally from the first floor of a building (5.0 m from the ground) at a speed of 5.0 m/s, where will it
r-ruslan [8.4K]

The ball will be 49.5m from the base when it hits the ground based on 9.8m/s² earth gravity.

what is earth gravity?
Gravity is the force by which a planet or other body draws objects toward its center. The force of gravity keeps all of the planets in orbit around the sun.

Why do things fall down when you throw them or drop them? The answer is because gravity ; an invisible force that pulls objects toward each other. Earth's gravity is what keeps you on the ground and what makes things fall.

First, let's try to find the time taken by ball to reach the ground :

-h = 0 - \frac{1}{2}gt^{2}

t = \sqrt{2gh}

t = \sqrt{2*9.8*5

t = 9.9 s (rounded)

Next, we will find the horizontal distance covered by ball :
D = v*t
D = 5 * 9.9

D = 49.5m

Therefore, the ball will be 49.5m from the base when it hits the ground for the first time based on 9.8m/s² earth gravity.

Learn more about earth gravity brainly.com/question/11174601

#SPJ4

8 0
1 year ago
A rocket traveling at 80 m/s is accelerated uniformly to 152 m/s over a 18 s interval. What is its displacement during this time
IgorLugansk [536]

Recall that with constant acceleration,

x_f-x_i=\dfrac{v_i+v_f}2t

where x_f-x_i is the rocket's displacment, v_i is its initial velocity, v_f its final velocity, and t is time. So

x_f-x_i=\dfrac{80\frac{\mathrm m}{\mathrm s}+152\,\frac{\mathrm m}{\mathrm s}}2(18\,\mathrm s)=2088\,\mathrm m

or just 2100 m if taking significant digits into account.

8 0
3 years ago
Use newton's method to find the second and third approximation of a root of
Nina [5.8K]
Please answer this question 

5 0
3 years ago
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